negative frequency ?

hi, how do i interpret fourier transform of a sinusoidal signal F[cos(w0*t)] = pi*[del(w-w0)+del(w+w0)]

-- why is there a negative frequency component at -w0 ? we used only a cos signal with positive frequency

--shouldn't the transform be just {del(w-w0)} as i have used a cos signal with UNIT amplitude. so why does pi appear in original transform ?

--why is the FT of sin(w0*t) a complex function. shouldnt it again be {del(w-w0)}

Reply to
brazingo
Loading thread data ...

It's all just mathematical book-keeping to keep track of the cos and sin parts separately.

Complex numbers are used in order to distinguish between sine and cosine signals. The convention is that the imaginary part corresponds to sine, and real part corresponds to cosine. If BOTH sine and cosine transformed to del(w-w0) (as you seem to think they should), there would be no way to distinguish between sine and cosine in the frequency domain.

As for the negative frequencies: it's more mathematical slight-of-hand. The complex coefficients on the transform are such that, when you add the positive and negative frequency parts, you are left with a real-valued function. Which the original time-domain signal must be.

Mark

Reply to
redbelly

ElectronDepot website is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.