In an avionics book i read that the IF of a reiceiver is 29.05 Mhz. How does that figure come out? Does it come out by the difference between the incoming radio signal and the Local oscillator frequency? Am i saying it correctly?
I think I would put it another way around: The designer of the radio chose to use 29.05 MHz as the IF, and designed the IF amplifiers to pass that frequency. The frequency that the receiver will receive is that IF frequency plus (or minus) the local oscillator frequency.
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Peter Bennett, VE7CEI
peterbb4 (at) interchange.ubc.ca
Since the local oscillator is normally at a *higher* frequency than the IF frequency - the received frequency is the LO frequency plus or minus the IF frequency (single conversion assumed).
In article , snipped-for-privacy@hotmail.com (known to some as thejim) scribed...
Yes to both questions.
I would offer a minor spelling correction ('receiver' as opposed to 'reiceiver'), and I would also say that 29.05 is only one example of an IF. It is by no means standard across all receivers.
Example: Motorola has used IF's of 45MHz, 10.7MHz, and 17.9MHz in various land/mobile 2-way radio products. GE/Ericsson has used 10.7, and many others.
There are still other receivers that use more than one IF (dual- conversion or triple-conversion).
Happy reading.
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Dr. Anton T. Squeegee, Director, Dutch Surrealist Plumbing Institute
(Known to some as Bruce Lane, KC7GR)
He seems to think that it's common, or done at all, for the LO to be _added_ to the received frequency, resulting in an "IF" that's the _sum_ of the frequencies.
On Mon, 30 Jan 2006 23:20:51 GMT in sci.electronics.basics, Rich Grise wrote,
I gather this system is used in premium wideband scanner designs so that image frequencies are far away and easily filtered out of the very high freq 1st IF.
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