DC Wave Questions

Jun 10, 2005 362 Replies

What did Eugene have to say? And tell me, do you know who Jim Roberts and Eugene Miya are?

If we have you using Roberts as a supporting witness, and Eugene (yes Eugene and I have met) as mine... you do realize that you're off the deep end again? (Roberts is somewhat of a net loon. Eugene Miya is a net legend.)

You've proven that you aren't the first twit that I've poked enough to cause erruption of tantrums. You can't say I didn't warn you not to try a flame war...

Floyd L. Davidson Ukpeagvik (Barrow, Alaska) floyd@barrow.com

sqrt(-1) is just as imaginary as 1 is.

Kevin Aylward snipped-for-privacy@anasoft.co.uk

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SuperSpice, a very affordable Mixed-Mode Windows Simulator with Schematic Capture, Waveform Display, FFT's and Filter Design.

No it isnt. An argument is a connected series of statements intended to establish a proposition...

next...

Kevin Aylward snipped-for-privacy@anasoft.co.uk

formatting link
SuperSpice, a very affordable Mixed-Mode Windows Simulator with Schematic Capture, Waveform Display, FFT's and Filter Design.

I guess you missed the part about that I was disagreeing with Pig Bladder about his contention that it wasn\'t just contradiction. next...

Nothing was deleted!

The style may be proper by your standards - certainly not mine - but the [content] is dead wrong. Nowhere did I refer to Don. We were talking about The Phantom.

John

--- No, and I don't care. What I found was that someone, about a year ago, pegged you for the same phony you are today. The phony, BTW, you have proved yourself to be by making all sorts of ridiculous claims which you later had to issue hasty disclaimers about when you were caught.

---

--- Interesting. I need no "supporting witness" but, again, you seem to have this need to latch on to someone's coat tails in order to be considered credible. From your performance here I can certainly understand why.

---

--- You either flatter yourself or you're used to playing with babies.

---

--- Yeah, like a Chihuahua yapping at a Rottweiler, LOL!

-- John Fields Professional Circuit Designer

Sorry, your time's up.......

Ken

Is this the five-minute argument, or the full half hour?

"Electricity is of two kinds, positive and negative. The difference is, I presume, that one comes a little more expensive, but is more durable; the other is a cheaper thing, but the moths get into it." (Stephen Leacock)

[some stuff]

Problem is, you're losing miserably... ;-P

The Pig Bladder from Uranus

So? Did anyone claim there was?

Bud's useage meets widely accepted and well known English. What *you* think about it is immaterial.

Provide some context that demonstrates it then, because it doesn't appear to be what you are now claiming.

Floyd L. Davidson Ukpeagvik (Barrow, Alaska) floyd@barrow.com

The only person that matters here is Don, and that he knows I didn't insult him.

Get a life.

John

--- Since, by your own admission, the boiling and freezing point temperatures of water are pressure dependent, I invite you to state what pressure would be required to be exerted on a volume of liquid water in order to cause it to boil at 0°C.

-- John Fields Professional Circuit Designer

I apparently did not make myself clear. My comment was not about Don Lancaster, nor did my post in any way allude to Don Lancaster, nor did the post I WAS commenting on refer to Don Lancaster.

Bud's post did not make a damned thing clear by screwing up and adding adding "[Don Lancaster]."

Did I make it abundantly clear?

On the other hand, it's nice to hear he did it using proper style.

Don

So, you miserable, troublemaking piece of shit, you\'ve decided to take on John Larkin? Big mistake. There\'s no way you can even begin to think about getting close to his track record, let alone even get into the stadium, so why don\'t you just quit before you embarrass yourself by not even being able to leave the starting blocks?

The boiling and freezing points are pressure dependent. Not only that, a certain amount of heat must be lost or gained (latent heat, I believe, is the term) before the change of state occurs. I am simply going by memory of my old Physics classes, and I have no idea what pressure would be required to allow water to boil at 0 C. I think other substances have boiled at lower temperatures than that at STP though.

Tom

"Tom MacIntyre" wrote in message news: snipped-for-privacy@4ax.com...

Strictly speaking, the change of state occurs as the latent heat is transferred, not after.

If you peruse the phase space of water at

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you will see that there is no liquid/vapor boundary at 0 oC. At a range of pressure well below standard atmospheric, it could happen near 0.01 oC.

John's challenge is a bit of a trick and appears to show he knows how to read that graph and accompanying table.

--Larry Brasfield email: donotspam_larry_brasfield@hotmail.com Above views may belong only to me.

Good one, John!

Best regards, Spehro Pefhany

"it\'s the network..." "The Journey is the reward" speff@interlog.com Info for manufacturers: http://www.trexon.com Embedded software/hardware/analog Info for designers: http://www.speff.com

At one atmosphere of pressure, the "latent heat of vaporization" of water is 540 calories per gram and is the amount of heat required to change liquid water at 100°C into steam at 100°C. That\'s used to great advantage, in reverse, in steam heating systems where steam which has been generated in a boiler is forced to condense into liquid water in a remotely located radiator and release that heat into the environment surrounding the radiator when it (the steam) changes state.

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