Current source?

I built a circuit to deliver a 40mA pulse on top of a 10mA DC offset. The 40 mA pulse is for 100uS.R4 & C1 set the approximate 100uS time constant. I'm thinking there must be a way to rapidly discharge C1 when the switch opens using fewer components then R11, X1, and Q6 plus an RC filter for the SCR gate. I tried just a PNP still takes milliseconds same with a JFET. This current scheme is the quickest about 20uS to bring VC1 down enough to turn Q2 off.

The schematic is here.

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Any suggestions?

Reply to
Hammy
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Transistor Q6 should have a turn-on resistor (Q6 base to ground), instead of having the load turn it on, when the switch is released.

Brian Ellis

Reply to
Brian Ellis

Use a 555 one-shot to contol your output transistor. Replace everything to the left of Q5 & its resistors with the one-shot.

Ed

Reply to
ehsjr

Yes I guess that's what I'll do.

I was trying to do it on the cheap with penny transistors and thick film resistors. The SCR at half the price of a TLC555 kind of defeats that purpose though.

Thanks all for the suggestions

Reply to
Hammy

I thought I'd give it one more try. I used a jfet P-channel to discharge the cap at switch off. It drops the cap voltage to zero in 230uS not spectacular but good enough. Load current drops almost instantaneously. I tried a JFET before and it wasn't fully discharging the cap. I must have had a wire crossed somewhere because it works well now. With a lower RDSON JFET I could improve that but for 23 cents for the FET I can't complain.

New schematic.

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The load is really a photo mosfet driver not two 1n4001's, R10 is for current sampling. So the total parts count is 11 and price about 50 cents.

Thanks again

Reply to
Hammy

It looks like J1 is a dead short to ground. You probably want an N-MOSFET instead, and you'll need a resistor to pull the gate to ground when the switch closes.

Regards, Bob Monsen

Reply to
Bob Monsen

No that's a P-channel JFET. It will only conduct when the switch is open Vgsoff (max) =4V.When the switch is closed the JFET is off. When the switch opens it provides a discharge path for the capacitor RDSON*C. Once the cap discharges the JFET drain is at zero volts, the switch is open so there is nothing for it to conduct. RDSON for the J176 is 250 ohms.

I didn't take direct current measurement but there is no need. I just measured the rise time of the cap which is 750uS through the 820 Ohm R4. The fall time is roughly 1/3 that so RDSON must be roughly 1/3 R4. It just gets warm (not hot) after repeated switching for testing.

Reply to
Hammy

Odd, I must have looked at it wrong before. Sorry about that.

Regards, Bob Monsen

Reply to
Bob Monsen

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