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Work transiestors better vertical?

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Not meaning to. It was a bit of a shock to me too. Take a one-turn circular optical path of radius R and refractive index n, initially at rest, with a source and beam splitter at one end of a diameter and a beam combiner at the other end, where the fringe shift is measured.

If you imagine light leaving the beam splitter at T=0, it arrives at the combiner at time t_half = pi*R*n/c.

If you then spin it at an angular rate of Omega rad/s, you might expect that the fringe shift in cycles would be equal to twice the number of wavelengths the combiner moved in the time it took the light to get there from the beam splitter, i.e.

Delta phi = 2*t_half*Omega*R*n/c.

Except that it isn't. The factor of n doesn't change anything; the phase shift is the same as in vacuo.

Cheers

Phil Hobbs

--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC
Optics Electro-optics Photonics Analog Electronics

55 Orchard Rd
Briarcliff Manor NY 10510
845-480-2058

email: hobbs (atsign) electrooptical (period) net
http://electrooptical.net
Reply to
Phil Hobbs
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started

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manufacturers:

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But isn't the idea to use a beam going the opposite direction as a reference? The idea being that both are in the same medium so c/RI drops out, leaving only the difference in the path length?

Reply to
krw

In Blackburn, Lancashire, but they could (maybe) have filled Albert Hall. Lennon himself seems less than 100% sure that they would have actually filled Albert Hall-- he was simply looking for a word to complete his verse:-

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And modern analysis casts further doubt on the theory:-

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Best regards, Spehro Pefhany

--
"it's the network..."                          "The Journey is the reward"
speff@interlog.com             Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog  Info for designers:  http://www.speff.com
Reply to
Spehro Pefhany

The tilt sensors on the pinball machines I've fixed had no semiconductor parts at all. One is a bob with a ring around it, and the other is a ramp with a ball and microswitch. ;-)

Cheers! Rich

Reply to
Rich Grise

On a sunny day (Thu, 16 Jun 2011 00:06:30 -0400) it happened Spehro Pefhany wrote in :

Actually the 'sea of holes' is not from the white double LP, but from the one with yellow submarine, not sure if that was an album, or part of Sgt Pepper?

Reply to
Jan Panteltje

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OK, mostly I had not thought about the case of the beams in something other than air (~vacuum). So is there any effect from the glass index of refraction. I'm thinking of the Fizeau drag. (Which I've never quite understood.)

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George H.

Reply to
George Herold

This was from work on ring gyros, not fiber gyros, probably mid 80's thus predating SPIE's on line journals which start from 1990. They once had an on-line index of all journal articles, but I can't find it now. If you can find an index to older Optical Engineering journals look for the first few years of articles on laser or ring gyros, sorry I can't be more specific. I think after the first few years continuing work on ring gyros became classified and details of deployed systems were not published.

Glen

Reply to
Glen Walpert

Try searching on "lock-in reduction".

Reply to
Spehro Pefhany

On a sunny day (Thu, 16 Jun 2011 11:36:10 -0600) it happened m II wrote in :

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Ah, thank you, yes, it is more complicated it seems, with different releases. I remember all those tracks, And I still have some as mp3 (no sea of holes).

Loved that music.

Reply to
Jan Panteltje

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Thanks, George H.

Reply to
George Herold

Skybuck. Its that you?

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Paul Hovnanian     mailto:Paul@Hovnanian.com
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Matter cannot be created or destroyed, nor can it be returned without a
receipt.
Reply to
Paul Hovnanian P.E.

Don't forget 'Goat' tube shields!

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in the lower right corner

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It's easy to think outside the box, when you have a cutting torch.
Reply to
Michael A. Terrell

No need. It's right under dimboobie. :)

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It's easy to think outside the box, when you have a cutting torch.
Reply to
Michael A. Terrell

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