Third Party Tests Conducted

May 21, 2013 28 Replies

Well, why are they using thermal imaging of a unit sitting in open air, instead of a system which can measure the ACTUAL heat output? This method is prone to HUGE errors due to emissivity, and the convective/conductive heat transfer is simply ESTIMATED, no attempt to even measure it! If you pumped water into a calorimeter and weighed the amount of water turned to steam every hour, you'd have an EXACT value of heat produced.

Then, if the thing is heating to 800+ C, why do they need to keep the heater on at all? This is the one that troubles me the most. Put some insulation around it and turn off the heater, and DISCONNECT the wires! Then, I would start to believe it. But, as long as the heater is still hooked up, I think there is funny business going on.

Jon

Not to mention that radiated power goes as T^4, which leaves huge opportunities for playing games. But I agree that they are most likely cheating on the electrical measurements.

That power meter is tacky. It uses clamp-on CTs, so ignores any DC power, or worse.

John Larkin Highland Technology, Inc jlarkin at highlandtechnology dot com http://www.highlandtechnology.com Precision electronic instrumentation Picosecond-resolution Digital Delay and Pulse generators Custom laser drivers and controllers Photonics and fiberoptic TTL data links VME thermocouple, LVDT, synchro acquisition and simulation

OOOhhh! I didn't catch that one! That's how they are doing it! Sine wave PLUS DC, fool the dummies! Easy to do, just put the DC supply in series with a transformer and hide it under a cardboard box.

Jon

They are using some mysterious trade-secret waveforms from some magic controller box. The DC component may be deliberate fakery, or could be self-delusion. Lots of folks start fooling people by fooling themselves first.

A healthy slug of DC can saturate a cheap CT and even make the AC component read low.

John Larkin Highland Technology, Inc jlarkin at highlandtechnology dot com http://www.highlandtechnology.com Precision electronic instrumentation Picosecond-resolution Digital Delay and Pulse generators Custom laser drivers and controllers Photonics and fiberoptic TTL data links VME thermocouple, LVDT, synchro acquisition and simulation

I like it.. the fancy signal is DC.

George H.

Trade secret!

I've wondered if a household disk-type power meter actually meters a half-wave rectified load accurately.

John Larkin Highland Technology Inc www.highlandtechnology.com jlarkin at highlandtechnology dot com Precision electronic instrumentation Picosecond-resolution Digital Delay and Pulse generators Custom timing and laser controllers Photonics and fiberoptic TTL data links VME analog, thermocouple, LVDT, synchro, tachometer Multichannel arbitrary waveform generators

According to Wiki as well as the principles of operation, a DC component

will not register accurately with an induction type watt-hour meter:

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The newer electronic types, and most professional power analyzers, use Hall effect sensors and instantaneous V*A readings to give true RMS voltage, current, and power readings as well as VA (apparent power or Volt-Amps Reactive), and thus power factor. Such a system can be purchased for under $3000 or rented for about 1/10 that:

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-500A-/321129602939

Many are even much less:

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g-Included-/251277365666 ($750)
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($200)

If they did not use something comparable to these instruments, then I think it can be safely concluded that they are either promoting a scam or are clueless about power, and their credibility ranks among those deluded denizens of the over-unity ilk who expose their ignorance on YouTube and

elsewhere on the web.

Paul

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