Hi everyone! I need some advice regarding closing the feedback loop of a halfbridge voltagemode smps. I need to calculate the power circuit gain. As far as I know, this is determined by taking transformer peak secondary voltage divided by modulator pwm-ramp amplitude. In my case, there are 2 secondary windings which both provides 75V peak (at 220Vac mains). So, 75 divided by 2.5 which is the pwm ramp amplitude, comes out to 30. Each secondary are connected to a fullwave buck-output filter and rectification. The error-amp is powered between both secondary rails. The supply will regulate at +/- 50Vdc. The error-amp is hooked up so it will actually "see" an output of both rails, which is 100V. (It's using -50Vdc as reference) So, to my question #1: As far as I can see, this arrangement results in doubled power circuit gain, correct? Question #2: Is there any other difference in placing the error-amp in this way compared to placing it just to "see" one of the rails and use secondary ground as reference. Excuse for describing this rather clumsy...Please forgive me for that. If there are any kind person out there who think he/she has the time to look into my questions, I'll gladly provide you with additional information if something's unclear in my description.
Best regards, Stefan