The short answer is, given what you know, don't even try. Learn more about electronics first, then start playing with power from the wall when you're not going to kill yourself, burn your house down, or shock your kids silly.
If you don't understand why you can't connect your equipment straight to the wall power without isolation, then you need to learn more about electronics and about how houses are wired for power before you can safely proceed to play with 120V. While it isn't always instantly LETHAL!!!, getting a shock from 120V always hurts a lot, it _can_ kill you on a bad day, and there's a lot of ways that you can build your equipment so that it doesn't kill you or your loved ones, but still burns down your house.
Get yourself a copy of the ARRL manual. They've got whole chapters in there on power supply design, electric safety, how houses in North America are wired, and all that useful stuff. Then READ IT. If you don't feel you understand what it says, don't mess around with 120V -- just find a wall-wart that delivers what you need, and be happy.
My liberal friends think I'm a conservative kook.
My conservative friends think I'm a liberal kook.
tem2c639b54d3 This power supply accepts 62VDC input, so if I use one rectif ier diode to rectify 120Vac home's power (decay to ~ 54Vdc), it will work ? 120Vac -> 1 rectifier diode -> 54Vdc -> Buck DC-DC power supply. Thanks.
This power supply accepts 62VDC input, so if I use one rectifier diode to rectify 120Vac home's power (decay to ~ 54Vdc), it will work ? 120Vac -> 1 rectifier diode -> 54Vdc -> Buck DC-DC power supply. Thanks.
The RMS voltage of a waveform is the DC voltage which would heat a load the same amount as the waveform under question.
For example, since Vrms = Vpeak/2 for a half-wave rectified sine wave, that signal, with an amplitude of 2 volts, would heat a load the same amount as 1 volt, DC would.
The average DC is the number you'd get if you took a great number of equally time-spaced voltage samples from the start of one half-sine pulse to the start of the next, added them all up, and then divided that sum by the number of samples.
In the end, that quotient would be equal to Vdc = Vpeak/pi.
Somewhere I have a 230VAC theraputic lamp/heater - it used to have a UV ray tube and used a pair of heater bars with combined rating of 115VAC to act as ballast for the UV tube and provide Theraputic IR rays. When the UV tube is not required (or missing) the heater bars are fed by a hefty rectifier diode, by clipping the half cycles; the power delivered to the heater bars is halved.
Unfortunately, with a buck converter; it doesn't work like that - the input filter/reservoir electrolytic will charge to 1.414 x 110V.
Of course with a buck regulator the transistor is in series with the load, so when the severely over-volted transistor fails short-circuit - the load should provide a short, but spectacular fireworks display.