I am a hobbyist with limited understanding of electronics curcuit design, so that's why I am turning here for possible help.
I have an wired electronic "barking dog" alarm that is triggered by a PIR motion sensor outside my entry way. The PIR is connected by a
4-conductor telephon wire to the inside "barking" speaker box that is also connected to the power supply. I bought this alarm about 25 years ago from Heath/Zenith. I would like to put its PIR sensor to dual use to also trigger a new X10 burglar interface device that works with low voltage input.After some testing I discovered that two wires (green and yellow, aka GY) of the phone wire connection between the PIR and the "dog" are really soldered together on the PCB, so in effect there are only 3 conductors between the sensor and the dog. The other two wire colors are black for the ground (B) and red for + (R.) I also found that when the PIR is in inactive state, the voltages are as so: between B & R: 5.06 V between B & GY: 0.19 V between GY & R: 4.69 V.
Then, during activation (for about 2 secs:) between B & R: 5.06 V (unchanged) between B & GY: 1.5 V (raised from 0.19 V) between GY & R: 3.32 V (dropped from 4.69 V)
When I saw this, I figured that the voltage between the B & GY conductors would also be a good candidate to also trigger the low voltage input of my new burglar alarm interface. The 1.5V created between those two conductors when PIR sees a motion is high enough to also trigger my burglar alarm but here is the rub: so is the 0.19V that exists there during inactive PIR. This means that I have to somhow make that 0.19V -> 1.5V change into 0V -> 1.5V change for the new burglar alarm interface. I figure this would probably be simple to accomplish with a diode that presents an open circuit below -- say -- 0.5V and shorts above it. I'm just guessing. Perhaps an appropriate relay would provide a better solution. In either case, I wouldn't know the specs for such diode or relay that I could use to buy them either online, or at places, such as Frys. Could you help me with this? Thanks.