" Geocacher" schreef in bericht news:dgu6ht$g24$ snipped-for-privacy@ctb-nnrp2.saix.net...
This is the place for some brillant questions. How often is that pulse send? How long does is last? What current does it expect? How much do the LEDs take? Is the voltage of that pulse the same as the normal operating voltage? Is that 12V or 24V or other? Is that pulse also send when the lights are on?
Why can't you keep that lights on? Or do they continue to simulate that disco? What's the flash rate?
Why? I've done that kind of things some more times. It's obvious that the computer is to old to recognise the LED assemblies but apparently a modification of it - let alone a new one - is more expensive then the bulbs or resistors. I feel with you that it does not satisfy the technician but economics rules you know.
Well, telling the computer requires a current high enough to make it think it sees incandescent bulbs. Bulbs or resistors come first into mind as you already know. You can circumvent it only if you have acces to the inside of the measuring system. It's almost sure that somewhere inside is a small resistor in the pulse circuit, used to measure the current by measuring the voltage accross it. If you can replace that resistor by a larger one, the voltage accross it will increase so the system will "see" more current.
Another approach is to provide the bleeding resistor only when the computer sends the measuring pulse. That's why I asked so many questions above. When the pulse comes, the resistor is switched on by a transistor, a timer keeps it on as long as the pulse lasts and switches it of afterwards. It's some simple classical electronics once you know how to detect the start of that measuring pulse.
Can't call that innovative. It's stretching the lifetime of an otherwise obsolete computer system. Can nevertheless be attractive.
petrus bitbyter