just wondering if there is a reference out there that goes into lotsa detail about using BJT current sources as collecor loads in analog amps. why can't i look at the output of an actively loaded gain stage (open loop) with a scope? if it's a "current output," shouldn't the scope's input Z turn the current into a voltage? the authors brush over this in Art of Electronics, though there is plenty of detail about current sources and mirrors themselves. in the AoE, it is stated that an active load should not be heavily loaded, or much of the gain will disappear, but if it's a current output, shouldn't the next stage be low Z for best current transfer? i'm so confused.
one more thing about differential stages loaded with a current mirror: with a differential amp, i thought the differential signal was represented by the collector current difference between the two transistors (before conversion to a voltage). but the mirror forces the collector currents to be largely equal. why doesn't this eliminate the output signal?
if one wants to actively load a differential stage, and have a differential output at the same time, how does one go about this? the current mirror restricts you to a single ended output, since the gain on the diode-connected BJT side is low.
please help! thanks.
Sean B