Puzzling diode

The fancy I-V curve tracers will produce a family of curves that are necessary to display transistor gain characteristics. You don't need that for a simple diode.

It's the one I recommended, but please don't assume I like it. It won't work for your diode anyway. The peak voltage from a 12VAC xformer is about 17V peak. With that low an output voltage, you'll never see the knee of the zener curve for a 79(?) volt zener. The transformer needs a higher voltage. Above about 48VDC, things become a bit dangerous. Remember, you have but one life to give for your hobby (or profession).

You don't really need to run it on AC. All AC gives you is the ability to see what's happening with both the forward and reverse conduction curves in the same plot on the oscilloscope screen. If you use a variable voltage DC power supply to "draw" the forward and reverse curves independently, you get the same result. The circuit is really simple. The diode is in series with a resistor to limit forward current. X-axis (voltage) goes across the diode. Y-Axis (current) goes across the series resistor. If your power supply has a grounded negative lead, use a 4 trace scope and differential inputs to keep the scope ground isolated.

Another way to do this is to use the sine wave output of an audio generator. Connect a step up transformer to the audio output to get up to maybe 90 volts peak. Keep the series current low (both forward and reverse) because the transformer can't handle much DC current. You should get a usable trace on the scope across the diode.

Yep. That's the way a zener works. Just make sure that when the zener conducts, the current through the zener is low enough to not blow up the zener when it conducts. Mostly, that means use a large value series resistor.

Reply to
Jeff Liebermann
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But the thing is when I lowered the voltage below 40v, it blocked current until the voltage was raised again. Starting at 46v & "breaking down" at 64v. Repeatedly. It wouldn't do that if it was melted, would it?

Reply to
Bob Engelhardt

Did you tell us the voltage drop versus a range of forward currents? Since this is for educational purposes, I would open one to see how it is constructed. I am guessing that there was no Si to melt, and it might have been made of Ge, especially if it has a point contact, or if it is a pellet with a spring-loaded contact, or if looks like one contact is "soldered" on (alloy junction made with indium).

Reply to
jfeng

snipped-for-privacy@gmail.com wrote: ==========================

*** FSS finish your sentence. Broke down to what ? 6V ? That is what you posted earlier.

Zeners do not have 2 voltages.

FYI Reverse breakdown a regular diode is usually fatal.

..... Phil

Reply to
Phil Allison

snipped-for-privacy@my-deja.com wrote: ====================

** The OP claimed 1V at 3 amps and "getting warm". Which is clearly bullshit. 3W dissipation in a small pack means it would be damn hot.

..... Phil

Reply to
Phil Allison

If you're judging the breakdown voltage by the temperature of the zener, you are unlikely to get an accurate. measurement.

If you have meter and can turn your AC test signal into DC, with a diode and capacitor, you'll get a better idea.

The aim in nondestructive testing is to burn up the series current limiter first, because it's cheaper and there are probably more of them, lying around.

V^2 / R .

RL

Reply to
legg

OK, it was too hot to touch. What I was trying to say was that it wasn't so hot as to be destroyed. It seemed like it could run "forever" at that current.

Reply to
Bob Engelhardt

It looks like something was lost along the way and you didn't get the last part of my sentence that read "...'breaking down' at 64v." See above.

This isn't marked as a zener & at breakdown: the voltage isn't fixed. I don't think it is a zener. Nor does it seem like a plain diode from its crazy behavior at breakdown. I.e., the breakdown not being fatal.

Reply to
Bob Engelhardt

Zener tolerance test current levels, above 48V are usually less than 10mA.

RL

Reply to
legg

snipped-for-privacy@gmail.com wrote: ==========================

** So your "breakdown" = start conducting current ?
** WTF are you on about?

Zeners do not drop suddenly in voltage when conducting.

** So you say.

..... Phil

Reply to
Phil Allison

Never mind.

Reply to
Bob Engelhardt

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