Eeyore wrote in news: snipped-for-privacy@hotmail.com:
Why do you feel the need to insult someone that is trying to help you understand something?
A half amp is .5 coul/sec. This represents about 3.121 x10^18 electrons. A penny (1950 vintage) weighs about 3.1 gm and contains about 2.9 x 10^22 atoms. There are clearly quite a few electrons in that penny, but NOT a huge excess of electrons, normally.
Most chips have very small amounts of metal in them. Lets say the gate in question holds 1 mg of metal. (it is almost certainly MUCH less than that, but lets go with that for the moment) If it were copper, there would be about 9.3x10^18 atoms, so out of every three atoms, we would need to have 1 excess electron in order to have a charge of .5 coul.
The electric field is proportional to the charge and inversely proportional to the square of the distance between the charge centers(the dielectric thickness in this case)
A volt is a joule per coulomb.
For a parallel plate capacitor, V = q/C. so, what is the value of the capacitor we have charged inside that chip?
Lets say it is 1 pf. To charge the cap with .5 coul of electrons what voltage do we need? My calculations show 5x10^11 volts. That seems a bit over any gate rating I can imagine for any normal chips.
Even if the gate were 10 uF, a charge of half a coulomb would require 50 kV.
As I said before, current from charge on the chip is NOT a significant factor. VOLTAGE from charges on the chip ARE the hazard.
Do your own calculations and stop calling people names.