I have a 24 volt military truck that I use for snow plowing. In the past I've had trouble finding 6000 series 24 volt sealed beam lamps for the plow frame.. And when I did I have found them to be very expensive. So I came up with a circuit using a DPDT switch in which both the high and low circuit lamp filaments are wired in series when power is applied. I was very careful to initially select two lamps that drew exactly the same current when tested on my bench power supply. The arrangement has worked flawlessly for the past few years. The other night I had occaision to look at the lights from outside the truck while it was running. Charging voltage on a 24 volt system can run as high as 28 volts on a typical 24 volt system. Although I didn't try to measure the voltage accross each lamp, I noticed that one lamp is slightly brighter than the other on the low circuit. I'm assuming that filament is getting weaker and thinner and will likely fail shortly. And of course when that happens I'll lose the low circuit. I can rematch two more lamps but before I do the thought occurred to me if there was any practical easy way the equalise the voltage accross both lamps in order to compensate for any minute differences in filament resistance. I think that the total current, (two lamps in series) is about 5.0 amps. Thanks for any suggestions. Lenny
- posted
13 years ago