Exactly right!
Greg (Schindler)
Greg Hansen wrote:
Exactly right!
Greg (Schindler)
Greg Hansen wrote:
but 2a/a is always 2, so if a=0, then 0/0 = 2.
In other words, 0/0 is the limit of an infine number of equations, not all of which evaluate to 1.
John
Yoy bwon't find a mathematician to agree with you. And in most physical situations, the only sensible definition of 0/0 is "indeterminate."
Not all circulating current in superconductive rings is precisely 1 amp.
John
Except the positive feedback rails the output. So the circuit makes no sense. It sure ain't a divider.
Not a divider either! More like a subtractor.
I agree that 0-0 = 0
Look closely at the text and the graphics. Both avoid a denominator of zero.
Jibberish.
John
0/0=1 is sorta like the question of where is the extra dollar? 3 guests check into a $30 hotel room and each pays $10. The hotel clerk later realizes he overcharged the guests since the room was only $25 instead of $30. So, the clerk sends the bellhop to the room to refund the extra $5 and each guest takes $1 and the bellhop gets a $2 tip. Therefore, each guest has payed $9 for a total of $27 and the bellhop got a $2 tip, bringing the total expenses to $29.
But the room was $30 paid in advance, so what happened to the extra dollar?
-Bill
That had me thinking for a while, but the way I figure it, each guest has ended up paying £9, totalling £27 :- £25 for the room, and £2 for the bellhop.
The £2 belhop tip was deducted from the £27 total expenses, and not added on afterwards.
depends which way round you think of it.
Yes. From an engineering prespective, 0/0 means "there's not enough signal to tell what's actually going on, so find some other way to measure things here."
John
I don't need Spice to tell me that both opamps are always railed! Or what the voltage at QUOT will be if the obvious fixes were made; and that won't be +1.
It's self-explanatory.
John
Don't need to in this instance.
Flail away. But the opamp circuit is still railed.
John
for
Yes, something like that. Another one I heard years ago was finding a counterfeit coin amongst 12 coins using a balance scale 3 times.
One of 12 coins is counterfeit and weighs more or less than a good coin. How do you find the counterfeit coin using a balance scale 3 times?
For example, if you weigh 6 coins against the other 6, the scale will not balance, and tells you nothing.
How can you find the counterfeit coin with only 3 weighings?
I forget the answer.
-Bill
One of 12 coins is counterfeit and weighs more or less than a good coin. How do you find the counterfeit coin using a balance scale 3 times?
For example, if you weigh 6 coins against the other 6, the scale will not balance, and tells you nothing.
How can you find the counterfeit coin with only 3 weighings?
I forget the answer. ===============================================
---
+V +V | | | +---|--[R]--+ +---|-[10R]-+ | | | | | | 1V--[R]--+--|+\\ | NOM>----[R]--+--|-\\ | | >-----+-->QUOT | >-----+--------------|-/ DENOM>--[R]--+--|+/ | | | | [10R] | | | | | 0V -V -VHappy now?
-- John Fields Professional Circuit Designer
+V +V | | | +---|--[R]--+ +---|-[10R]-+ | | | | | | -1V--[R]--+--|+\\ | NOM>----[R]--+--|-\\ | | >-----+-->QUOT | >-----+--------------|-/ DENOM>--[R]--+--|+/ | | | | [10R] | | | | | 0V -V -V
Happy now?
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