Simple circuit to generate 12VDC from a 9v battery?

Mar 23, 2006 14 Replies

Hello everyone, I need to generate 12vdc from a 9v square battery, cheaply and simply, supplying about 20mA. I have looked at DC-DC convertors, but haven't come across anything suitable.



I found this circuit that does something similar with a 555 timer but it can only supply about 12mA. Any ideas how to increase the current capability a little?



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Any other simple circuit ideas welcome Thanks Marius



If you can tolerate a quarter volt of p-p ripple:

I think that one is pretty efficient. You can tweak R1 and R2 to get closer to 12V, but figure about 500k-1Meg total resistance for the pair and that you need some 1.23V at the FB pin.

Jon

Hello everyone, I need to generate 12vdc from a 9v square battery, cheaply and simply, supplying about 20mA. I have looked at DC-DC convertors, but haven't come across anything suitable.

I found this circuit that does something similar with a 555 timer but it can only supply about 12mA. Any ideas how to increase the current capability a little?

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Any other simple circuit ideas welcome Thanks Marius

Run the square wave from the 555 thru a custom wound transformer to get any voltage you want on the secondary?

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That circuit creates a negative voltage that is smaller than the supply. You need a boosting converter with a positive output. You need something arranged more like this:

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This should supply enough current, just put a 1K resistor on the output and a 12V Zener to ground (after the resistor) to clamp the voltage at

12V.

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supply.

output

Oops, I just re-read your post and you need 20mA out. Lower the 1K resistor I suggested to about 220 ohms and use a 1W Zener.

^^^^ Ah, well 9V squared is 81V, plenty to use a resistor to drop down to 12V. ;o)

Tim

-- Deep Fryer: a very philosophical monk. Website:

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And if you still don't get enough current out, reduce the value of R2. Output current from a doubler circuit like that is proportional to frequency.

Another approach is to use a switching converter IC, such as the MC34063A. Take a look at the drawing at

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Brian

--- Try this: (View in Courier)

. . +9V +9V +9V . | | |A . [1000R] +---+---+ [1N4148] 78L12 . | |_ Vcc | | +-------+ . +------O|D OUT|--[10µF+]-+-[1N4148>]-+--|IN OUT|-->+12V . | | | | | GND | . [10kR] +--|TH 555| +| +---+---+ . | | |__ _| [10µF] | . +----+-O|TR R|O--+9V | GND . | | GND | GND . | +---+---+ . | | . [10nF] GND . | . GND .

-- John Fields Professional Circuit Designer

Or, better yet,: . . +9V +9V +9V . | | |A . [1000R] +---+---+ [1N4148] 78L12 . | |_ Vcc | | +-------+ . +------O|D OUT|--[0.10µF+]-+-[1N4148>]-+--|IN OUT|-->+12V . | | | | | GND | . [10kR] +--|TH 555| +| +---+---+ . | | |__ _| [0.1µF] | . +----+-O|TR R|O--+9V | GND . | | GND | GND . | +---+---+ . | | . [100pF] GND . | . GND .

Det var smuk og solrig dag da royalmp2001 skrev news: snipped-for-privacy@i39g2000cwa.googlegroups.com i sci.electronics.basics:

How about two 1.5V batteries in series with your 9V battery. That is simple, and you don't throw away a lot of energy in conversions.

Rune D. Jørgensen

Indeed. In the same vein, why not just get rid of the 9V battery and run it from a 12V battery?

This thread reminded me of a funny error from a freshly graduated electronics engineer that we hired some years ago. He needed something like

7.5V from a 5V power supply, so he simply wired a resistor voltage divider in "reverse", ie he connected 5V to the output... Luckily I spot the error before he made a pcb for it.

--DF

"royalmp2001" wrote in news: snipped-for-privacy@i40g2000cwc.googlegroups.com:

simply,

5volts.

Try this one at

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roma

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