Circuit 9V ->6V

Dec 15, 2008 9 Replies

I am working on a small circuit that blinks a LED that I will create multiple items of to place around my kids's apartment windows to hopefully deter bad guy, flashing led could mean alarm, etc. Found a good circuit but it calls for (4) AA batteries and want to modify the input to support 9V source instead of the (4) AA batteries.



The little kit, costs about $4.00 is perfect with the exception of the source, have tried to simulate with



9V source with various divider circuits to lower to output to 6V with min current to drive the LED?

Sorry for such a basic question but it's been (20) years since I have played around with this stuff!



Thanks!


Duh!, Right, looking for it now, I purchased these years ago and have the PCB as a kit and thought I had the schematic, still looking!

I finally said f it as I could not find the schematic and simply hooked it up to a 9V source, so far no heat build up on the (2) transistors or other components, now wondering if the source will last longer or burn out the parts quicker, will check the voltages after an hour or so

Measure the current the thing draws, maybe you can just drop the volts with a resistor or zener.

Tom

i've found that these days, things aren't nearly as sensitive to power supply voltage as they used to be. whether it's those little wall wart things which are horribly unregulated, or things that are run by 9 volt battery or off 12 volts from a cigarette lighter socket without benefit of any circuitry in between;

i've found that these days, things aren't nearly as sensitive to power supply voltage as they used to be. whether it's those little wall wart things which are horribly unregulated, or things that are run by 9 volt battery or off 12 volts from a cigarette lighter socket without benefit of any circuitry in between;

True quite often.

Tom

On Dec 15, 7:56 am, PinkFloyd43 wrote, in as far as I can tell now:)

I give good chance that that the circuit will work plenty well from 9V instead of 6V if all resistors that are in series with LEDs have their values doubled or multiplied by 2.2 or use commonly available values close to roughly or slightly over doubling.

If the circuit is intolerant of voltages closer to 9V than to 6V, then it has great chance of working at 5V - use the common 7805 5V voltage regulator IC (which has only 3 pins) to drop the voltage. Put a diode in series with the "ground pin" if you want 5.5-5.6 volts, 2 diodes if you need more like a bit over 6 volts. Maybe use 1N4148 if using one diode, or use 1N400* if you use 2 diodes.

- Don Klipstein ( snipped-for-privacy@misty.com)

Put 4 1N4001 diodes in series between the 9V battery and the circuit. Each diode will drop the voltage by approximately .6 to .7 volts.

Ed

This was the type of answer I was looking for Thanks!

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