Neither parallel nor series

Oct 20, 2004 10 Replies

What theorem or method can be applied to calculate the total resistance at point A to B?



----- A ----- | | | | R1 R2 | | | | ------R3------ | | | | R4 R5 | | | | ----- B -----



Thanks.



Star to delta conversion will work here.

Your above star connection can be converted into equivalent delta connection, like this

RB ___ |--------------|---|___|----------------| | | | | | | | | | | | | .-. .-. B RA | | | | RC A | | | | | '-' '-' | | | | | | ___ | | ___ | |----|___|-----|-----------|-----|___|--|

R5 R2

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RA = ( R4*R1 + R1*R3 + R3*R4 ) / R1

RB = ( R4*R1 + R1*R3 + R3*R4 ) / R3

RC = ( R4*R1 + R1*R3 + R3*R4 ) / R4

Now it is easy enough, for you to further simply it.

Use Delta to STAR conversion,

the result became, and it is series with parallel series.

A > | | |

Ra = (R1+R2)/(R1+R2+R3) Rb = (R1+R3)/(R1+R2+R3) Ra = (R2+R3)/(R1+R2+R3)

it is in Electrical technology by Edward Hughes

KM

I think there is a correction here, Ra should equal to (R1*R2)/(R1+R2+R3) and Rb, Rc as well. So the total resistance is (Ra + ((R4+Rb) || (R5+Rc))) Let say, R1=1k, R2=2k, R3=3k, R4=4k and R5=5k. I will get the answer of 2.9k and it is same with my simulation. Thanks !!

whoops, what an ugly mistake i did; feeling very shameful. should be delta to star. really frustrating isn't it??should go and die somewhere.

somewhere.

If that is the biggest mistake you make this year, you are doing better than most of us.

John Popelish

well i hope so.

thanks

You forgot to say "I don't like doing my own homework, please do it for me."

And the correlary: if this ISN'T a homework problem, you should say so. It also would help if you mentioned what you've tried so far, and whether you're an absolute beginner or not.

--------- Nothing:

The formula is wrong for delta to star conversion- try Ra=(R1*R2)/(R1

+R2+R3) etc This will give you 1 ohm.

In the case where R1/R4 =R2/R5, you can simply remove R3 as it won't have any effect. (figure out why).

Don Kelly dhky@peeshaw.ca remove the urine to answer

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