Basic Ohm's Law E P ----------------
---------------- I R E I
What simple Ohm's Law formulas get combined to (Exp.E=RxI E=P/I} to arrive at I=SqRt of P/R V=SqRt of P*R P= V^2/R
Thank You for any advice Frustrated Apprentice
Basic Ohm's Law E P ----------------
---------------- I R E I
What simple Ohm's Law formulas get combined to (Exp.E=RxI E=P/I} to arrive at I=SqRt of P/R V=SqRt of P*R P= V^2/R
Thank You for any advice Frustrated Apprentice
"rdelec"
** P = VISubstituting V/R for I, gives P = Vsquared / R
-------------------------
V = P / I
Substituting V/R for I, gives V = P * R /V
So V squared = P*R
------------------------
I = P / V
Substituting I*R for V, gives I = P /I*R
So, Isquared = P/R
..... Phil
I can't read your formulas so well, so I will repeat them.
E=I*R P=E*I
If substitute the first expression that equals E for the E in the second formula, you get P=(I*R)*I=I*I*R=(I^2)*R.
If you take the square root of both sides of P=(I^2)*R you get sqrt(P)=I*sqrt(R). Then dividing both sides by the sqrt(R) you get sqrt(P)/sqrt(R)=sqrt(P/R)=I.
If you rearrange the first to solve for I by dividing both sides by R, you get E/R=I. Then you can substitute this equivalent of I for the I in the power formula. P=E*(E/R)=E*E/R=(E^2)/R.
If you take the square root of both sides of P=(E^2)/R, you get sqrt(P)=E/sqrt(R). Multiplying both sides by sqrt(R) you get sqrt(P)*sqrt(R)=sqrt(P*R)=E.
Is that what you needed?
-- Regards, John Popelish
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