Important ! for u

It is indeed resolution.

For someone supposedly involved in electronic design you don't know very much do you ?

Graham

A 16-bit converter has 2^16 possible states; a 24-bit converter has 2^24. But note that in the real world this difference is *very* hard to realize, due to the noise floor of typical analog circuits. That's because there are definite limits on how high the input voltage can be, so you have to try to resolve ever-lower voltages to increase resolution. With a 16-bit ADC having a 0-4.096 V input range, the resolution is 62.5 microvolts. With a 24-bit ADC covering the same range, the resolution is 0.244 microvolts. Not many circuits with noise that low!

Best regards,

Bob Masta dqatechATdaqartaDOTcom D A Q A R T A Data AcQuisition And Real-Time Analysis

Home of DaqGen, the FREEWARE signal generator

Hi, Joshua. May I suggest that you find a tutor, and pay him to help you with your school project.

You are in way over your head, and a newsgroup is not the appropriate place to get the kind of timely, intensive help you apparently need. This newsgroup is also not an appropriate place for homework questions.

I'm sure you could either place a post on your school bulletin board, or advertise to find an upperclassman who is willing to be employed.

Good luck Chris

To a certain extent I agree, yet the OP has chosen s.e.b. (rather than s.e.d. at least) and at least has asked a question (albeit not using particularly precise grammar ;) and perhaps even wishes to learn - who knows.

I always thought s.e.b. might be the appropriate place for someone to ask a question on an electronics subject about which they have no knowledge, especially if they admit to not knowing :)

Cheers

PeteS

For someone posting on the basics newsgroup you are rather rude. If you don't want to help someone, don't make fun of them. this isn't SED, and the OP isn't claiming to be an EE, so get over yourself.

--
Service to my country? Been there, Done that, and I\'ve got my DD214 to
prove it.
Member of DAV #85.

Michael A. Terrell
Central Florida

Hi, Pete. You're right, of course. A few people have said the unofficial motto of s.e.b. should be that "There's no question too basic for this newsgroup". We don't want to scare off the newbies.

Look at his 15 topic posts over the last two weeks in s.e.b., s.e.d. and sci.electronics.components, and judge for yourself. Look particularly at the posts relating to his weigh scale project, load cells and the LCD display. I'm thinking in particular about his post early this morning in s.e.d. "Hi, All (Load Cell)", and the several following spam posts, "please help me".

He really needs much more help than the advice he can get here, and he's not being fair to himself looking for that help in newsgroups. His project will never get done by the end of the semester. And incidentally, I've heard it expressed a few times here that the function of homework and class projects is to reinforce learning, and we're defeating that purpose by serving up answers to homework questions.

Joshua is apparently in so far over his head that a good answer to his question might not even help. If he does understand anything about digital logic and counting, he doesn't indicate it. And if he did, the most appropriate response here would actually be to have somebody find out what Digital Logic textbook they're using in his class, obtaining the book, then typing up the chapter on ADCs in a post (including illustrations in ASCII art ;-). He really should just read it himself, and purchase the textbook if he hasn't done so. Sometimes there are no shortcuts to learning -- you just have to do it. We did.

Every college and technical school has sharp kids who are looking for a few extra honest coins (I would have included myself among those back in the day). It might be better for him to just find one, and get some tutoring and/or design help with his project. If he doesn't understand the classwork, several hours a week of one-on-one intensive help might get him on track quickly without a whole lot of expense.

I do like the fact that nobody's flaming him here, including me. I wish Joshua well, and hope he gets all the help he needs.

Cheers Chris

you are correct, its basicly how accurate you can decode an analog signal. results of the lowest and highest value would most likely be the same as lower bit converters how ever, each reading you get is of larger scale number between the same range as that of the lower bit converters. for example.. an 8 bit coverter has a range of

0..255 , 0 = 0 volts, 255 = 10 volts for example. a 16 bit converter has a range of 0..65535, 0 = 0 volts, 65535 = 10 volts...

you can see here that between the low and high you can get more accurate readings. now sampling rates is still another story.

--
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5

Well, there are some who seem to continue to ask questions on 'advanced' things without asking for basics first , although that (for a few posts anyway) is perhaps understandable - they don't know there are basics underlying the question.

After a few such posts, provided we've explained that the OP might like to ask very basic questions where we could even point to a resource on said basics, it does tend to get old.

That said, I didn't see the posts in question (I was netless for a while on a job - aarrgghh) so I don't know this particular history :)

I think I get more pee'd at poor grammar and spelling than apparently silly questions - after all, if I can't understand the question, there's little hope of answering it !

I don't doubt you had no intention to flame :)

Cheers

PeteS