How does this circuit work? Is it a pre-amp?

MRW · 2007-07-03T20:58:03+00:00

Hello!Happy 4th of July to my American colleagues!I have this circuit: How does it work?I initially thought that the first opamp is a microphone pre-amplifierin an inverting configuration and the second one is used to invert thesignal back. But when I looked at it again, the second opamp isconfigured as a voltage follower. Why is that?I think that C6 and C7 are just used as a bypass capacitor for anynoise coming from VCC. R20 and C5 are just high pass filters that willroll off any signal below 8Hz. R15 and R17 are used to biased theinput at half of VCC for single supply operation.Is that the right assumption?I also have a feeling that if the first opamp is indeed a pre-amp,then it's gain is frequency dependent. But how do I find out theequation for it? Is it just (-R13)/(reactance of C5) ?Any other insights into this circuit?Thanks!

Jul 03, 2007 20 Replies

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Jasen Betts 19 years ago

something to wrap the wires round. A 5mm drill bit would work (and willbe exactly 5mm) 22swg is stiff enough to hold its shape after the bit is withdrawn. (leaving the drill bit in place would foul everything up)

Bye. Jasen

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How does this circuit work? Is it a pre-amp?

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