I'd like to build a circuit to turn off some of the equipment on my fish tank for maybe 10 minutes during feeding time.
Is there a low-parts-count circuit I can build to shut off AC power to a socket for that amount of time when I push a button?
I've been scribbling with 555's, comparators, relays, power supplies and stuff, but I'm wondering if I'm overlooking something simpler.
All suggestions welcome.
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H
Homer J Simpson
120 Volts? You need an industrial delay on timer. You press a button to turn it off, another one and after the preset time it will turn on.
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E
ehsjr
This should do it for you:
+--------+--[Relay]---+-------+ | | | | | +-----|
J
Jonathan Kirwan
I don't know how much of a load you are talking about.
Since you've been looking at all that, I won't feel sheepish about posting a schematic I saw in sci.electronics.design a while back.
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You'd need a 9VDC source, though. Most folks will recommend that the
9V be isolated from the AC line via a transformer, so there is that, too. (You might be tempted to develop the 9V more directly from the AC line to save the transformer, but keep in mind that pushbutton.)
Since the operating current is about 10mA during that 10 minutes you want, a 9V battery (nominally, they are spec'd at 25mA) will run for about 100 hours down to about 5V, which may not be enough to operate the relay (the one I mention there is available at Digikey for $5.56 in ones, they have stock right now, and it specs a minimum of 3.75V to operate) for all that time. But if you get even 20-50 hours out of it, that may be enough for you. So a 9V battery would be an option, I think.
You can use a lower voltage, or higher, but you will need to adjust C1 and R3 to set the timing. The duration is something like:
-ln( Vth of M1 / Vsupply ) * R3 * C1
I think the Vth is about 3V for the BSS145, but I haven't checked it. With Vsupply=9, R3=5.6M, and C1=100uF, I get about 615 seconds delay, which is close to 10 minutes.
Jon
R
Randy Day
[snip]
J
jasen
yeah, one of those delay buttons: one part.
Bye.
Jasen
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