Why there exists phase difference between current and voltage?
- posted
12 years ago
Why there exists phase difference between current and voltage?
ELI the ICEman cometh!
Plz make me understand.....
Voltage across a capacitor cannot change instantaneously. Current has to change first. Therefor, I (current), in a C(apacitor), comes before E (voltage).
Current through an inductor cannot change instantaneously. Voltage has to change first. Therefor E (voltage), in an L(inductance) changes before I (current).
The old[*] ELI the ICE man.
[*] old == from the days when ice was delivered to the door.
Grocery and liquor stores may still have an Eli.
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IThank you for helping me out.
Sorry you didn't like my response. :-(
Reactance.
Hope This Helps! Rich
@rich:can u tell me how the reactance is responsible for phase difference?
Reactance is not responsible for a phase change. Reactance of a capacitor and reactance of an inductor have units of ohms.
A google search for "reactance is responsible for phase difference?" found this link:
That resource is approved.
-- It most certainly is.
Globemaker Inscribed thus:
Now try reading the next page !
-- Best Regards: Baron.
I _can_, but I think you're either supposed to get that from your textbook or your teacher.
Good Luck! Rich
--- @BBC:
Here, I'll take crack at it:
When a voltage is applied across a conductor and charge starts to flow, a magnetic field is generated around the conductor which causes a voltage to be generated in the conductor which opposes the applied voltage.
This opposition is in addition to the ohmic resistance of the conductor, and is called "Inductive reactance" or, written symbolically, "Xl" (X sub L)
Now, since time is nature's way of keeping everything from happening all at once, the magnetic field doesn't build up instantaneously and, as a consequence, as the voltage across the inductance varies, the current through it won't fall in step.
Do you understand?
-- JF
You know, I think the best way to understand about R, C and L might be to build circuits and measure things with 'scopes. (and the proper scope probes) But I can't remember every doing that in college.
George H.
Instead of investing all that time and all those resources, why not just use SPICE?
-- JF
Think about a capacitor charging through a resistor. When you apply the voltage, the capacitor starts charging with maximum current and minimum voltage across the capacitor. As time passes, the capacitor voltages increases while the current decreases, since the voltage across the resistor becomes less and less, and so does the capacitor current. So, the current and voltage of the capacitor are out of phase, since one will reach a maximum at the same time the other reaches a minimum. The capacitor voltage reaches a maximum when the current is zero, and visa versa. That's 90 degrees. The inductor is the opposite, where current starts at zero and rises, while the voltage across the inductor falls.
-Bill
Hmm, Yeah the difference between a simulation and real life. No arc's when you unplug the coil at full current in the simulation.
George H.
Confucius say: I hear and I forget. I see and I remember. I do and I understand.
Hope This Helps! Rich
-- Arc is??? Take a look at the top of the coil for a clue. ;) Version 4 SHEET 1 880 680 WIRE 208 208 96 208 WIRE 304 208 288 208 WIRE 416 208 384 208 WIRE 416 256 416 208 WIRE 96 272 96 208 WIRE 224 272 224 256 WIRE 96 384 96 352 WIRE 224 384 224 352 WIRE 224 384 96 384 WIRE 272 384 272 256 WIRE 272 384 224 384 WIRE 416 384 416 336 WIRE 416 384 272 384 WIRE 96 464 96 384 FLAG 96 464 0 SYMBOL voltage 96 256 R0 WINDOW 123 0 0 Left 0 WINDOW 39 0 0 Left 0 SYMATTR InstName V1 SYMATTR Value 10 SYMBOL voltage 224 256 R0 WINDOW 0 -53 5 Left 0 WINDOW 3 -242 110 Invisible 0 WINDOW 123 0 0 Left 0 WINDOW 39 0 0 Left 0 SYMATTR InstName V3 SYMATTR Value PULSE(0 1 1 1E-6 1E-6 10) SYMBOL sw 304 208 M270 WINDOW 0 32 15 Left 0 WINDOW 3 32 44 Left 0 SYMATTR InstName S1 SYMBOL res 400 192 R90 WINDOW 0 -35 56 VBottom 0 WINDOW 3 -30 58 VTop 0 SYMATTR InstName R1 SYMATTR Value 1 SYMBOL ind 400 240 R0 SYMATTR InstName L1 SYMATTR Value 10 TEXT 104 408 Left 0 !.model SW SW(Ron=1 Roff=1e9 Vt=0.5Vh=0) TEXT 102 440 Left 0 !.tran 20 startup
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