Bi-color LED help

Is this a trick question? :-)

yes, install a 3 lead shared anode led is the simplest.

or get two standard LED's and hook them up as a standard 3 lead shared anode.

Don...

this maybe. K1 A ----|

--- Please bottom post.

There's not enough information in your post to give you actual circuit values, but here's the basic idea: (View in Courier).

| \\ | \\ IN>--+--| >O---O| >--+ | | / | / | | [R] | | | [LED] | | \\ | +-----------| >O-+ | /

"IN" is one of the signals used to drive the 3 lead LED.

If the LED's colors light up reversed, just swap the LED in the circuit.

You may be able to get rid of two of the inverters depending on what "IN" looks like. Post some more information about your circuit and you'll get more help.

-- John Fields Professional Circuit Designer

You could modify your circuit if both LEDs are *not* lighted at the same time: +--------+-----o | | + V red V gn - - | | .-. .-. | |Rred | |Rgn | | | | '-' '-' | | |/ |/ -| -| |> |>

| | === === GND GND

| | === === GND GND (created by AACircuit v1.28 beta 10/06/04

"Lucky225" schreef in bericht news: snipped-for-privacy@p79g2000cwp.googlegroups.com...

As so often, it depends.

Suppose the cathodes are driven by (microcontrollers) outputs that can source and sink enough current *AND* you only need one of the colors at a time *THEN* you can simply connect the 2 lead component between the cathode cathode joints of the original LED. You may need to add a resistor to limit the current. If the outputs cannot source enough current, you need buffers. If the outputs can only sink current, you can use the upside-down circuit. See below.

CA | | C1---||---C2

Original 3 lead bi-color LED