color changing led problem

I bought some color changing led's. It works well with 9v batteries but when I got home and tried it with 12v (planning to use it on my car) and a 750ohm resistor it just lit red and didnt change color. Tried again with lower voltage starting at 1.5 gradualy moving up without resistor... it changed color at 6v - and then burned! What am I doing wrong? It worked well with the 9v battery so why did it burn at 6v? Any ideas on how to get it to work?

Thank you very much and good day

Reply to
Patrick
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If there is any possibility of getting a data sheet on the LEDs, or at least the recommended operating voltage and current, that would help you design the bias curcuit properly. Without a data sheet on these LEDs, all I can offer is a bit of guesswork.

My guess is that the LEDs don't have an internal resistor, so an external resistor is necessary to limit current. Without a current limiting resistor, diode current rises very fast once the turn-on-voltage has been passed, and a burned-out LED is the usual result.

Your 750 ohm resistor with a 12v source may have been a bit large. It would limit current to under 15ma. Maybe you need a more current to get into color changing mode. Try reducing that resistor to something smaller; maybe 600 ohms or 450 ohms.

As for why it worked with a nine volt battery even without a resistor, the battery may have been weak enough that it self-limited the current to a safe value. I'll bet that the LED would have burned out quickly enough when powered by a freshly charged 9v battery.

Just guess work, but I hope it helps.

Reply to
Blake

dont do that

Reply to
Marlboro

LEDs are current-operated devices and need a limiting resistor to prevent excessive current. Connecting the LED directly to a power source is generally a recipe for failure...

The reason the LED worked at "9 volts" is that the battery is limited in the amount of current it can deliver and the battery voltage dropped when the LED was connected.

You need to limit the LED current to something around 20 ma (milli-amps) for testing.

Reply to
John

All, Instead of guessing, trial and error, and smoking those leds which stink badly there is a formula for this: R = (Vcc-Vled)/Iled where where R = resistor to put in series. Vcc = supply voltage Vled = Led voltage across the Led Iled = led current

Michael

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Reply to
Michael Monteith

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