You've just added in a simulation of an infinitely long lasting power supply.
Making a real negative resistor along those lines would involve having a real infinitely long lasting power supply. Last time I checked, they were hard to come by.
Sylvia.
You've just added in a simulation of an infinitely long lasting power supply.
Making a real negative resistor along those lines would involve having a real infinitely long lasting power supply. Last time I checked, they were hard to come by.
Sylvia.
Positively excellent retort.
And to think that you fat, retarded bastards have been calling me a troll.
I would say zero current flow. As in open circuit.
Certainly the current tends towards zero as the resistance tends towards infinity (or minus infinity).
But for a resistance that is "greater than infinite"? Not possible to say without a definition of the term.
Sylvia.
slope
I haven't tried. I don't see what point you think you're making.
Sylvia.
Not as much fun, though ;-)
-- "Electricity is of two kinds, positive and negative. The difference is, I presume, that one comes a little more expensive, but is more durable; the other is a cheaper thing, but the moths get into it." (Stephen Leacock)
You should adopt that as a sig, John.
-- "Electricity is of two kinds, positive and negative. The difference is, I presume, that one comes a little more expensive, but is more durable; the other is a cheaper thing, but the moths get into it." (Stephen Leacock)
It's a bad photo to judge from, but Sylvia looks emaciated... that's pushing "skinny" just a wee bit too far ;-)
...Jim Thompson
Obstinate? See the SIG, you're blundering along riding a collection of bad assumptions.
It's alright, around here, to admit error. Actually, it's admirable, it happens so rarely ;-)
...Jim Thompson
slope
I still don't get it. If I run the transient response, just as you set it up, the opamp output is stuck near ground and the V3 source sees a load of about 1K to near ground, plus the opamp supply current. The opamp is just an expensive ground.
So what's the function of the circuit?
John
I've run your sim, comments posted elsewhere, and I can't figure out what the circuit is supposed to do.
John
he
is
ede
nNo, it follows Ohm's law with a minus resistance value:
V =3D R * I
The value of R is negative.
lYou seem not to understand that there are two types of negative resistors. Both are validly negative. Try thinking about the conductance of a negative resistor. Consider passing resistance through zero and then consider passing conductance through zero. You will see that they don't both take you to the same place.
There's cause to think that neither you nor I are gorgeous burning hunks of male beauty.
John
I did a walk through the Cornell EE department. Just for fun, I counted oscilloscope screens (three) and PC screens (had to be a hundred, maybe.)
My office is a little better, three oscilloscopes (as many as Cornell!) and two PCs. I actually own about 40 scopes and 5 PCs.
John
Hardly ;-)
But does your "skinny" preference descend to "bony" ?:-)
...Jim Thompson
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