"Jim Thompson" wrote in message news: snipped-for-privacy@4ax.com...
Such as...?
The document there does have a "pinciples of operation," so roughy speaking it's clear how it works. I'd be happy to take a shot at explaining my own understanding of it, though: For the 15V supply... the goal, of of course, is to use Q1 as a pass transistor such that of the ~24V you get across filter capacitor C1 ends up as 15V between the output (anode of C2) and power ground (what they call "voltage common").
When the output is in regulation, Q4/Q5 split ~ (15V - (8.2V [marked on schematic for base of Q4]+0.6Vbe) )/910=6.8mA. The ~3.4mA through R8 pulls Q5's collector up to ~ -12.6V+3.4mA*5.6kohm = 6.4V. As for regulation... if the +15V rail were to go up a bit, Q4's base voltage will also go up a bit, thereby turning Q4 off a bit, causing Q5 to get a bit more of the shared
6.8mA, which will cause its collector voltage to rise. Q1/Q2 are a Darlington pair emitter follower... with Q5's collector rising, Q1's emitter voltage will rise as well, thereby reducing the voltage between the +15V rail and power ground. Poof! -- We have regulation!Hmm... I suppose Q5's collector should actually sit at closer to -1.4V (the two Vbe drops of Q1 and Q2), now that I think about it. Tying Q5's collector to -12.6V via R8 (and similarly for R7) does strike me as making for a controlled/tracked output voltage startup as another poster mentioned, although I haven't spent the time to really understand that yet.
For overcurrent protection... when Q3 begins to turn on at around
0.6V/0.36ohms=1.67A (hmm... seems rather high; the document says 800mA), Q3 effectively begins to reduce the Vbe of the Q1/Q2 follower pair, so it can no longer supply additional current. For overvoltage, VR1 kicks in if Q2's base is > 14.7V with respect to the Q1/Q2 pair's collector ... that's more just protection of Q1/Q2 from some fault condition rather than just, e.g., someone feeding back in > 15V at the output, I think?How's that for a start?
---Joel