What does mV/V-mA mean?

May 04, 2015 7 Replies

Hello,



I'm looking at a current sensor datasheet, it says



Sensitivity up to 2mV/mA (on the front page/Key Features)



and



sensitivity is typ. 0.08mV/V-mA @ 5V Supply (In the operating specifications)



What does this mean?



My guess:



I have the part and did some measurements



with a 5V supply



I put 4mA through it and got 6.6mV out I put 5mA through it and got 6.9mV out



so... (6.9mV-6.6mV)/(5mA-4mA) = 0.3mV/1mA = 0.3V/A ?



if I took the 0.08mV/V-mA number and multipy by the supply voltage I get


0.08mV/V-mA * 5V = 0.4mV/V-mA? which is close to 0.3mV/V-mA

Here's the datasheet:



formatting link


I think I've screwed this up, can anyone help explain this?



Thanks!


Den mandag den 4. maj 2015 kl. 20.20.13 UTC+2 skrev Fibo:

I'm guessing, millivolt output per volt supply per milliamp current

-Lasse

Yep. If you look at the schematic the bridge is powered by the rail, not off some internal reference, thus is sensitive to power supply. ...Jim Thompson

| James E.Thompson | mens | | Analog Innovations | et | | Analog/Mixed-Signal ASIC's and Discrete Systems | manus | | San Tan Valley, AZ 85142 Skype: skypeanalog | | | Voice:(480)460-2350 Fax: Available upon request | Brass Rat | | E-mail Icon at http://www.analog-innovations.com | 1962 | I love to cook with wine. Sometimes I even put it in the food.

ahhh.... mV/V-mA = mV/V/mA..... doh! Thanks!

One one thousandth the figure for mV/V-A

Volt Amps.

Volt Milli-amps. It simply allows the resultant figure to appear more intuitive.

On Mon, 4 May 2015 12:55:33 -0700 (PDT), Fibo Gave us:

NOT per.

TIMES.

VA is Volts TIMES Amps.

V-mA is Volts TIMES milliamps.

The figure is a metered output figure described as mV of graph or bar movement per *given figure*. It is way to make the output more readable and pertinent to the values being read.

On Mon, 04 May 2015 15:33:47 -0500, Tim Wescott Gave us:

Thank you for articulating it well. I was stumbling.... I think.

Fibo is correct. But either way is correct.

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