I have Netgear Wireless Router (from U.S.A) that needs a input of 120v AC ~ 60Hz 16W
Here in India, I bought a Voltage Converter which convert from
220/240v AC ~ 50/60Hz 20W to 110/120V AC 20W
Converter doesn't mention what is the converted value of 60Hz.
Question: Is it safe to use this Converter with the Netgear Router. Will 20W input to 16W requirement ruin the router?
Thanks!
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R
Robert Baer
Be *careful* !!! A number of cheap "converters" is nothing more than a diode and is "good" only for heaters and incandescent lights (the life of those will be severely decreased). There are some converters that are transformers, and so safe to use. Frequency will not be changed, so if your power is 50Hz, the output will also be 50Hz - which for most equipment is acceptable.
S
Swan
Will 20W input to a 16W requirement damage the router?
I got the converter checked using a multimeter and it converts to
110v
P
Phil Allison
"Robert Baer"
** No such silly thing exists - you pathetic half wit.
....... Phil
S
Spehro Pefhany
No. That would give you double the wattage. There's a bit more than a simple rectifier in there (think 'dimmer').
If it's rated for only 20W and heavy it should be fine.
Right kind:
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(also a splendid example of the capabilities of HTML)
Wrong kind:
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Best regards, Spehro Pefhany
"it\'s the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
S
Spehro Pefhany
No. 20W is a maximum, but in practice with something electronic like that 16W is about at the maximum due to the way it draws current. It might get warm (the converter) but both converter and router should be okay.
Good. If it was the "wrong" kind of converter it would read considerably lower than that unless the multimeter was a fancy-schmancy type.
Best regards, Spehro Pefhany
"it\'s the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
R
Robert Baer
Not relevant; one could use a 200 KW generator to run a 5W shaver. What kind of multimeter? If analog, the reading is not meaningful as it is an average. If a DVM, i cannot say if that reading is relevant or not. A transformer-type converter has some weight to it - about a pound or so; a diode type is usually smaller and is very light. The transformer types are billed as being useable for a shaver.
R
Robert Baer
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A diode does not "double" the wattage.
R
Robert Baer
Use your head for more than a hat rack; 1000W "converters" are sold and "plainly" marked "for heaters and irons only".
P
Phil Allison
"Robert Baer = F****NG MORON "
** Know them well.
They use triac dimmers circuits set to 66 degrees ( out of 180) conduction angle per half cycle.
NOT BLOODY DIODES - you F****IT
....... Phil
S
Spehro Pefhany
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In this case, a diode would "halve" the average wattage by giving you "half" of the cycles.
Now, let's do a little Gedankenexperiment-- what would the power dissipation of a "100W 120V" heater be if operated on 240VAC?
Best regards, Spehro Pefhany
"it\'s the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
R
Robert Baer
Well, if one had a square wave source, when the diode conducts, one has 240V during that time, for P=E*E/R or four times the power then; the other half of the time one has zero power; heating power is double as claimed. For a rectified/half sine wave, i do not know what the "RMS" would be, but i would think it would be less than 240V.
N
Nobody
The shape of the waveform doesn't matter, so long as the positive and negative halves are symmetric.
If you apply 240V RMS to a 100W, 120V RMS resistive load, you get 400W. If you halve the duty cycle with a diode, you get 200W.
Whether a square wave, sine wave, triangle wave, etc, halving the duty cycle halves the power and thus reduces the RMS voltage by sqrt(2).
S
Spehro Pefhany
Okay, assuming ideal diodes:
If you have a FULL wave 240V RMS sinusoidal source, the power is quadruple the 100W rating, or 400W.
If you have FULL wave rectified 240V RMS sinusoidal source, the power is STILL 400W because resistors don't know for polarity.
If you have a HALF wave rectified 240V sinusoidal source, the power is
400W average for the half-cycles that the diode conducts, and zero for the half-cycles that the diode blocks. So the average power is 200W, or double the rating.
No calculus required, although it's not difficult to do the definite integral of voltage*current over a half cycle for a sinusoid, which leads to the same conclusion.
Best regards, Spehro Pefhany
"it\'s the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
R
Robert Baer
Gotcha; now understand...
J
JosephKK
Spehro Pefhany snipped-for-privacy@interlogDOTyou.knowwhat posted to sci.electronics.design:
That is an ok 0th cut, too bad the heating element is a strongly temperature dependant device. It increases in resistance strongly with increased temperture, this helps it self regulate its temperature and consequently its power.
S
Spehro Pefhany
Yes, the simplifying assumption is made that the resistance of our imaginary "120V 100W" heater is constant.
Nichrome actually has quite a low TCR.. about 1/20 that of most pure metals or around +0.01-0.02%/K, which is not what I'd call "strongly temperature depend..nt". Maybe your imaginary heater is made of some other material or runs much hotter than my imaginary heater. Or perhaps you're thinking of an incandescent light bulb.
Best regards, Spehro Pefhany
"it\'s the network..." "The Journey is the reward"
speff@interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
J
JosephKK
Spehro Pefhany snipped-for-privacy@interlogDOTyou.knowwhat posted to sci.electronics.design:
Haven't looked at it for a long time, but i have had issues with wirewound resistors changing resistance with temperature. All of the resistance versus temperature curves i have seen look like a pure exponential curve, perhaps not paying enough attention to the vertical scale has tripped me up. I do remember that by the time it is glowing the resistance and power gets to acting pretty strange versus added voltage.
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