Wrong.
^^^^^^^^^^^^^ Nonsense.
Wrong.
Wrong. Since the postulation and confirmation of general relativity we know that gravitational effects are not (solely) based on mass, but rather more generally on the density of stress, energy, and momentum:
The Einstein Field Equations are in units where c = 1
G_ab + Lambda g_ab = 8pi G T_ab,
where
G_ab = R_ab - 1/2 R g_ab
is (a component of) the Einstein tensor, R_ab is the Ricci curvature tensor, g_ab is the metric tensor, R = g^ab R_ab is the Ricci curvature scalar, Lambda is the cosmological constant, and T_ab is the (stress--)energy--momentum tensor.
Gravitional effects are understood (in GR) as a consequence of the curvature of spacetime which is described by the quantities on the left-hand side of the equations.
The energy--momentum tensor of a 1+3-dimensional spacetime has 16 components, but it is antisymmetric so only 10 of them are unique. Anyhow, the time--time component is proportional to the energy density which is at relative rest is proportional to the mass density:
T_00 ~ rho_E ~ dE_0/dV = c^2 dm/dV = c^2 rho_m.
It does not.
IOW: This is way over your head.
As an engineer, though, you should appreciate the requirement to agree and conform to standards. That includes network standards which you keep violating by your address munging:
It is not. You are arguing from your ignorance.
It is possible, just very difficult:
The total energy of both photons has at least to be equal to the sum of the rest energies of the particle and antiparticle.
You would have to separate the particle and the antiparticle to prevent them from annihilating again, which means that the total energy of both photons has to be much larger than the sum of the rest energies of the particle and the antiparticle. You need energy for the magnetic fields that keep them separated.
A single electron is not very useful, indeed, and you need more energy to produce it this way than it could do usable work because it needs kinetic energy *and* rest energy E_0 = m_e c^2.
No, the total electric charge is conserved. What happens in "charging" is that electric charge is added from or removed to somewhere else.
Electric charge can also be "induced" by bringing an electrically charge in the vicinity of an electrically neutral object. Then the carriers of electric charge in the formerly neutral object arrange themselves such that the distribution of electric charge is no longer uniform:
.---------. ,---------. : (+) (-) : : (+) (-) : : (-) (+) : : (+) (-) : : (+) (-) : : (+) (-) : : (-) (+) : : (+) (-) : : (+) (-) : : (+) (-) : : (-) (+) : : (+) (-) : : (+) (-) : : (+) (-) : : (-) (+) : : (+) (-) : : (+) (-) : : (+) (-) : : (-) (+) : : (+) (-) : '---------' '---------'
Some time later:
.---------. ,---------. : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : : (+) (-) : '---------' '---------'
Nonsense. A changing electric field induces a magnetic field, and a changing magnetic field induces an electric field:
∇ × B = μ₀ J + (1/c^2) ∂E/∂t, ∇ × E = -∂B/∂t.