Unequivalent Input Impedance in Differential OpAmp Circuit

Using your sim and setting V5 and V6 amplitudes to 2V so they're the same amplitude opposite phase and the op-amp doesn't clip, and using your .tran simulation.

For your 1kHz burst INA and INB are pretty much the same amplitude because C101 and C100 are only about 160R at 1kHz.

The current through R41 is 300uA p-p and through R43 it's 100uA - the input impedance seen at INA is 13.3kR and at INB it's 40kR.

But for your common mode signal, the currents through R41 and R43 are the same. When INA and INB are equal, so are the input impedances at

40kR. If you increase the CM amplitude you can see in the 1kHz burst that the in-phase common mode current is the same in both resistors, while the opposite phase differential currents are 3:1.
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Cheers 
Clive
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Clive Arthur
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ot equal and in fact the value appears to be around 40 kohms on each input leg. I just can't explain that for a differential input signal.

Thanks for your reply. My signal sources are at 1 kHz (now) but I have als o used AC analysis over a range of frequencies, typically 20, 1k and 20k as well as locating the -6 dB frequency.

I have tested the circuit in common mode, differential mode and each of the two inputs separately. In every case the frequency response is the same w ithin experimental error (3 decimal places). Since the impedance of the tw o input capacitors must be the same over frequency regardless of mode of te st, I have to conclude the input impedance of the circuit does not actually change with test mode.

Or... in another thread someone pointed out that the gain of the two inputs is not equal and so the result is the appearance of equal frequency respon se at the two inputs. He did not provide a quantitative description so I a m not about to verify this. In fact the gain of the two inputs should be i dentical. That is the purpose of the resistors in the non-inverting input arranged as a voltage divider, to equalize the gain of the two inputs.

Another poster did a hand waving analysis using Z1 and Z2 without explainin g what he was using them for, so I assume they are part of some standard wa y of analyzing amplifier circuits. He wrote an equation for gain G= and one for T= which I don't recall what it stood for. He then massaged the equations and produced a result, none of which made sense to me since there was inadequate info.

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  Rick C. 

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Rick C

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