Thinking about a 80MHz crystal - as a detector

I'm thinking about the possibility of using high-Q 80MHz crystals in a sensitive electric-field detector.* You know, consider the usual amplifier in a high-performance crystal oscillator, but without ANY feedback path, and further modified so the amplifier doesn't excite the crystal, not even a little.

Looking at crystal models, the loss-resistance element may be on the order of 10 ohms, which implies a Johnson noise density on the order of 0.4nV per root-Hz. So an optimum kT-sensitive amplifier would need a similar noise level. Hmm, that could imply a rather large JFET with excessively-high capacitances. Certainly the JFET will be part of the crystal's tuning capacitance, but I'm probably going to be limited to say 10pF or less. A 2sk146 JFET has 1nV noise, but has 40pF of capacitance. A 2sk152 has 1.8nV with 8pF, that's getting closer. But 1.8nV is 4.5 times kT for a 10-ohm crystal...

Maybe a low-noise BJT amplifier would be better... I have some 2sd786 transistors, which state 0.55nV on the datasheet, for Ic = 10mA. Oops, then r_e = 2.5-ohms and with a beta of 500 Zin would be only 1.2k, not good enough to avoid loading down a sensor with Q = 20,000. BJT base-current noise would be another issue. Hah, JFETs suffer from a bit of current noise at RF frequencies, according to AoE, but no doubt much less than a BJT amplifier.

Another issue, fundamental vs overtone mode crystals. I've read that fundamental-mode crystals have much lower Qs than overtone mode, e.g., Corning lists a 4:1 improvement for 3rd versus 1st.

  • Don't ask about the application just now. It's a bit exotic, the same experiment that's getting the 10kV 1us precision ramp.
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 Thanks,
    - Win
Reply to
Winfield Hill
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Any possibility of inserting a transformer at the front?

steve

Reply to
Stephan Goldstein

Or low impedance series resonance...

Reply to
Fred Bloggs

Prove it- what makes you think it is Johnson noise, because it is represented as a resistor symbol?

Reply to
Fred Bloggs

Acckk, how am I going to do that? I'm making an assumption. Maybe someone else can give us an answer, references, etc.

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 Thanks,
    - Win
Reply to
Winfield Hill

It's back to basics for you. The book by Nye on the physics of crystal should have the answer. Physical Properties of Crystals, Oxford, still going through late editions, will be in nearly any technical library.

Reply to
Fred Bloggs

Just speculating, not sure what you're actually detecting, but do some Google searches for "microcalorimeter" and see if this is what you're trying to do. To oversimplify they are looking for energy deposited into a crystal giving some tiny phonons of quantum vibration, and looking for this at extremely low noise levels.

I know the nuclear physics side (hint: these experiments are usually buried deep in mines or inside mountains), but always got lost in the solid-state phonon stuff.

Tim.

Reply to
Tim Shoppa

I don't understand this. Is the crystal itself going to be exposed to the e-field, or is there an antenna of some sort, connected to the crystal?

If the crystal is used directly, is its metallization the antenna?

Is there any advantage over using the crystal in the front-end, as opposed to matching+amplification followed by a narrowband, maybe crystal, filter? A well-matched fet amp can have a noise figure well below 1 dB.

And of course, the crystal series resistance behaves, from a Johnson noise perspective, just like any other resistor. Conservation of energy, again. Ignoring microphonics.

John

Reply to
John Larkin

Wouldn't 80MHz fundamental crystals be mesa crystals? How does their Q compare to bulk crystals?

P.S. I think you'll get more grant money if you use MEMS resonators instead of boring old crystals. Nanotech would be even better.

Reply to
David DiGiacomo

The crystal's mechanical properties are actually somewhat anharmonic, which is why the overtones aren't in exact harmonic relationship. This could be used as a detection mechanism. Otherwise it sounds more or less like it's being used as a high-Q tank circuit for impedance transformation, which isn't altogether unreasonable.

Providing that there's a dissipative process going on, this is right, and that's what's going on in the crystal. The fluctuation-dissipation theorem again.

There was that guy ten years or so ago who made a big stir with a "lossless resistor" for switching circuits. I never really learned the details, but he got a big IEEE medal or something for it. Does anybody remember?

Cheers,

Phil Hobbs

Reply to
Phil Hobbs

AFAIK Johnson noise happens to any dissipative 'thing' that shows up as an electrical effect -- all that matters is the apparent resistance and the temperature. AoE actually mentions this.

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Tim Wescott
Wescott Design Services
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Reply to
Tim Wescott

Or an impedance matching network. One adjustable coil and a pair of caps will do almost anything you want them to, and you don't have to worry about the assembly being too narrowband compared to the crystal. If that doesn't float your boat then you can get 3:1 trifilar broadband transformers from Mini-Circuits that'll bring that optimal match up to

90 ohms -- still not good, but better at least.

Check out "Radio Frequency Design" by Wes Hayward -- he goes into detail about noise matching in an RF environment (which you should already know) but also about using transformer feedback to get a power match at the same impedance as a noise match.

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Tim Wescott
Wescott Design Services
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Reply to
Tim Wescott

In article , Winfield Hill wrote: [....]

Is there gas around the crystal? There will be noise from the atoms smacking into it, if there is.

Crystals aren't very linear at very small or very large signals will this be a problem?

Someone at Berkeley was using a tiny ring core to detect the magnetic field that the electrostatic one implies. You may want to google on this to see if it worked.

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kensmith@rahul.net   forging knowledge
Reply to
Ken Smith

wasnt it a transmission line followed by a dc-dc converter or somesuch?

I vaguely recall reading a paper at the time, but forget the details. ISTR his examples were all puny wee things,

Reply to
Terry Given

Reply to
Winfield Hill

:)

I wouldnt want a belt from one of your 10kV gadgets though (electroporesis perhaps?)

I just scanned thru the last 6 years of IEEE professional comics, and couldnt find a mention of it. but upon further recollection I think my explanation is roughly correct, and the examples he gave were about 50W or so. the lack of mention this century suggests it wasnt so great after all though.

I'm doing some design work at the moment for a 200KVA converter. Only problem is, there is nowhere to plug them in at home :( Even my neighbour (a joinery place) only has a 60A 400V outlet. So I'm going to make a 2kVA prototype first....

fault currents get quite exciting with the big stuff. IGBTs limit fault current to around 10x their rated current (depending, of course, on Vg) so my 300Arms converter has to cope with a peak fault current of about

4,000A. turning that off without going bang is a good trick.

I tried to estimate last night how much money has been spent training me over the last 15 years, its a LOT. Tens of millions of dollars. No wonder smart companies work hard to retain staff. I once destroyed $1,000,000 worth of fancy flywheels, one at a time :) (OK, its not that bad, I tried to operate them at their rated load etc, and they all failed in various ways)

on an analogous note:

Air NZ is looking at laying off a whole lot of engineering workers in NZ (they do all their own aircraft maintenance, and contract to others too). I wondered why, until a friend who is in the military set me straight. A few years back, we neutered our air force - we no longer have planes with guns; any offensive air capability will only come about through hiring saudi pilots ;) so the air force no longer trains all the associated personnel. So Air NZ cant hire pre-trained technical staff, but has to train them itself. which it cant afford....

Cheers Terry

Reply to
Terry Given

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