switching Vss with a transistor

Jul 25, 2007 2 Replies

Total hobbyist here.



Is there anyway to wire a transistor so that it closes the Vss instead closing the connection to ground?



I have a ciruit like this


Vss --------R1----+------------+ | | 3000 uF LED | | gnd --------------+-------------+


The capacitor provides a nice fade when Vss is switched off which is much more cool than just blinking.



So i need to wire this into the output of a sound actuation circuit (already done). But in order for the sound actuation circuit to drive the heavier load (100s of LEDs), I added a transistor.


Vss --------R1----+------------+ | | 3000 uF LED | | gnd---T1 ---------+------------+ | +5V in


This is how I see it done in my books and online

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but the problem is that the LED never gets the current bleed from the capacitor because the transistor switched off connection to ground. The other way around would work:



+5V in | Vss ----T1--R1----+------------+ | | 3000 uF LED | | gnd-----------------+------------+


But the transistor I'm using doesn't seem to want to work in this configuration.



Any ideas?



First, when you\'re drawing ASCII schematics, use a non-proportional font like Courier and _never_ use the TAB key, use the space bar. Second, try this: (View in Courier) +V | [R] | +-----+ |A |+ [LED] [BFC] | | +-----+ | C ACT>--[R]--B NPN E | GND But, _hundreds_ of LEDs???

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