Simple power supply overheating components, shorting zener

I have a simple power supply in a special voltage sensing relay that detects two valid voltage ranges, 90-130 VAC and 200-270 VAC. I have tested it at up to 280 VAC, 60 Hz, and everything is fine. It is in a well vented plastic octal relay enclosure. We have had two of these fail in the field (possibly in the same unit), where the 15 ohm 2W limiting resistor (R1) has gotten very hot, and the zener (Z1) has shorted. The schematic is about as follows:

R2 +-------------/\\/\\/---------------------> To A/D circuit | 100K 1W | C1 C2 D2 ACHI-+-)|---)|-----+--->|---+----+---78L05---> 5 VDC to PIC 2uF 2uF | 1N4004 | | | Film | | | | D1--- Z1/-/ -C1 | 1N4004 ^ 12V ^ -100uF| | | | | R1 | | | | ACLO---/\\/\\/-------+--------+----+-----+----- GND 15R 2W

The circuit draws about 110 mA at 250 VAC 60 Hz, for about 200 mW on R1. The zener diode (1N4744) should see only about half that, for about 600 mW. This device is in a circuit breaker test set that may be powered from nominal 120 VAC or 208/240 VAC supplies. It is unlikely that it would be powered from anything other than normal AC sine wave power, although it could possibly be from a generator. The only way I can see high current flowing through R1 would be from high frequency components on the AC line. I don't want to use resistors in place of C1 and C2 because they would drop

25W and get quite hot in the small package, and there is no room for a transformer. The test set would not work properly on a modified sinewave inverter or PWM supply, and I doubt that the customer would be using anything like that.

There are only about a dozen of these test sets in the field. A previous unit had an 18.2 ohm 1/4 W resistor for R1, which was marginal, so it was replaced with the 15 ohm 2 W. Any ideas about how this circuit might fail as described?

Thanks,

Paul

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Reply to
Paul E. Schoen
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What are the temperature limits on the various components and what temperature are they experiencing?

Reply to
Homer J Simpson

The ceramic power resistor got hot enough to discolor, and it melted a plastic IC socket next to it. I ran the circuit for about an hour, and the resistor was just a bit warm. I did not notice any other components with elevated temperatures. There is only an 8 pin PIC, and two dual solid state MOSFET relays in DIP packages. Ambient conditions are normal industrial/commercial temperature ranges, about 0 to 40 C. The inside of the test set might get hotter than that, but it is forced air cooled. I plan to run the test set at maximum output and try to see if the area near this component gets unusually hot.

Thanks for the quick reply.

Paul

Reply to
Paul E. Schoen

Dan Thomas

Reply to
Daniel A. Thomas

That is a good point. It might be as high as 25 amps at 280 VAC input. The time constant should be only about 15 uSec, however, so I don't think that would cause the resistor to overheat. It might explain the shorted zener, however, although the electrolytic capacitor across it should absorb the spike. Maybe the customer has a very noisy connector or switch that causes the voltage to turn on and off rapidly.

Paul

Reply to
Paul E. Schoen

I would doubt that if 7805 turns on and off for some line conditions and draw more current and power when it restarts its operation than in steady state. Did you try to increase the value of C1 and use 105C capacitor. You may also decrease the value to see if the problem occurs on your side. Why do you use 12 V zener by the way? did you try 15V?

Paul E. Schoen wrote:

Reply to
ksoner

tested

has

mW.

drop

Spikes on the AC line, or ACLO having a substantial voltage with repsect to gnd ... if this is connected ot the mains it can see harsh voltage spikes from other eqpmnt turning on/off etc.. I would suspect a basic generator is just as bad if not worse unless there is some sort of filter/protection.

Any spikes would cuase large currents to flow through the capacitors etc, maybe it might be worth using a capcitor from the end of c2 down to aclo to form a capacitor divider.

Colin =^.^=

Reply to
colin

I cant read the circuit too well but it looks like C!/2 are failing. Why do you have 2 caps in series? Are they rated for direct mains connection (X2) ?

Reply to
cbarn24050

There might be something else on the circuit that is injecting nasty high-frequency crap into the line, and series line inductance is allowing a lot of energy into your unit. For example, a noisy AC-motor inverter drive or something like that. Short of a proper transformer-isolated design, for a fix, my suggestion is an external power resistor of at least 100-200R (maybe a 5W-10W ceramic type). Check your zener surge rating and substitute a TVS if necessary to stay within the maximum ratings under all conditions (including transient). For future designs, I suggest you use a bigger octal case and put a suitable transformer in there if this is an industrial application. That kind of capacitive dropper 'stuff' is really only (barely) suitable for low-end consumer applications.

Best regards, Spehro Pefhany

--
"it\'s the network..."                          "The Journey is the reward"
speff@interlog.com             Info for manufacturers: http://www.trexon.com
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Reply to
Spehro Pefhany

Several potential problems:

(1) What is the voltage rating of those 2uF capacitors? It better be at least 600V each. Power lines have spikes on them! As a real-world example, when I open up old tube radios, about 20% of them have exploded capacitors across the 120V power line. Those caps are sometimes 200VDC rated paper capacitors, sometimes even 600VDC.

(2) Did you know that many types of metallized film capacitors are unabashedly designed to short out several times a second? The metal film is very thin, so the short clears itself as the film vaporizes, but you do get a heck of a current pulse.

(3) Imagine if the guy turns off the power switch just as the line voltage is at its negative peak. At 280 VAC that's 396 volts. Then he waits a second plus 1/120th of a second and flips the switch back on again. Now you have 392 volts positive from the line going into the lead of a capacitor that is charges to minus 392. That feeds your diode, the zener, and the 15 ohm resistor with SEVEN HUNDRED NINETY TWO volts. Current could be as high as SEVENTY EIGHT amps. Waay too much current for all the components involved.

(4) Even if the components can take the current, imagine what happens to that poor resistor. It has 700+ volts across its terminals. If it's one of those spiral-cut resistors, it could arc over from one turn to the next, likely leading to the same thing happening to the next turn, and the next, and the next.... leading to really high currents there for a few milliseconds. You need a resistor there with a continuous voltage distribuution insiude, like a carbon comp type. Even then I'd worry about it blowing apart.

Methinks you're in a no-win situation. How's about you buy a tiny wall-wart transformer, or such? See

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They're not expensive and a whole lot cheaper than pissing off your customers.

Reply to
Ancient_Hacker

oops, a few afterthoughts:

(5) I hope you're not making a 1uF non-polar capacitor out of two 2uF polarized reverse connected electrolytics! Many electrolytics are designed for smoothing applications where the ripple voltage is a small fraction of the applied voltage. In the two-capacitor case, that's not true. Plus since electrolytics have an up to 200% tolerance, the smaller one may end up with up to 50% reverse voltage applied across it. That's not a good thing.

Reply to
Ancient_Hacker

He says they're film. You can get film caps rated for 250VAC line voltage, but of course they are larger and more expensive than the ones that will work for a while then short.

Best regards, Spehro Pefhany

--
"it\'s the network..."                          "The Journey is the reward"
speff@interlog.com             Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog  Info for designers:  http://www.speff.com
Reply to
Spehro Pefhany

Spehro Pefhany a écrit :

But these are still not guaranteed to not show momentarily shorts.

--
Thanks,
Fred.
Reply to
Fred Bartoli

This circuit cannot work. It is a charge pump. It will kill the zener with the inrush current and then will pump up to 600V into the cap(without a load), yes it is a voltage doubler. It cannot supply more than 30mA(on 230V) either with a horrible ripple. Or are these 2u caps parallel? Why don't you use a bridge rectifier instead?

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ciao Ban
Apricale, Italy
Reply to
Ban

oops, right, they're film, the question is what is their voltage rating, and is it enough to guarantee them not shorting under all conditions?

Maybe you could fit a transformer in there-- a 1watt one at digi-key is only 1x1.3x0.8 inches. Downside: $12 !!

Or a complete 5VDC wall-wart from the same place is only $3.95! I'd seriously consider this unless it is awfully uinconvenient for the user.

Reply to
Ancient_Hacker

I believe the caps are 250 VAC polypropylene, although possibly 400 VDC. If a transformer were used, it would have to be rated at 250 or even 300 VAC primary, if the secondary is to be accurate enough for measurement (it cannot saturate). There is limited space in the portable test set. Cost is not a major factor.

Paul

Reply to
Paul E. Schoen

Alternatively you can do the whole shebang of voltage detection with a LP339 quad comparator and a snootful of resistors all which can run off microamps.

Or a CMOS quad schmitt NAND trigger with even fewer resistors.

Reply to
Ancient_Hacker

Probably huge line transients. There's a low-impedance path through the input caps and the 15 ohm thing, and it's all silicon after that.

Try replacing the zener with a transzorb, a zener rated for very high peak power. Better yet, use a small transformer supply or buy a tiny universal-input switcher.

John

Reply to
John Larkin

The circuit *does* work. The capacitors (in series) act as a voltage doubler, but the load of the zener diode and the 100uF filter cap limit the voltage, and absorb the energy on the forward conduction cycle. A bridge rectifier cannot be used because the measuring circuit must be referenced to the ACLO point. The 15 ohm resistor does add some error (about 1.5 VAC) to the AC voltage reading, however, so it might be better to move the reference GND to the ACLO line. I am very limited in space, so I cannot add more (or larger) components, unless I go to a SMT design.

Thanks,

Paul

Reply to
Paul E. Schoen

The GND in the schematic is an internal reference ground for the rest of the circuit. The capacitive divider might be worthwhile to consider, but I'd rather pump mostr of the energy into the filter capacitor across the zener. I will look at the waveforms with a scope to see if there is anything to be concerned about, but this circuit has only failed at the customer's site. I will see if I can talk to him and find out how he is powering the unit. I don't think random voltage spikes would cause the resistor to overheat, but possibly some sort of SCR phase fired regulator could be a serious problem with a repetitive sharp rise time waveform.

Thanks,

Paul

Reply to
Paul E. Schoen

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