Resonator Calculations

how to calculate the total capacitance of this resonator?

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should i first terminate the 2 ends with a 50ohm resistors or i can calculate it directly?

Reply to
redhat
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The natural resonance frequency is simply (1/2 Pi) * sqrt( (1/C7 + 1/C7A + 1/C7B) / L ) The capacitors are just in series w.r.t. the resonance. The actual peak frequency will depend on the source and load resistances and be somewhat lower, especially with 50 Ohms at each port.

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--Larry Brasfield
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Reply to
Larry Brasfield

Hi Larry, how could the capacitors be in series with each other, you haven't considered input and output ports? Hi Roger, you have assumed a frequency of 94MHz to convert the capacitor to series, what if i don't know the resonant frequency?

regards

Reply to
redhat

Download SCILAB from

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You only need a "Compact" installation Run this script (paste into editor window, then execute):

s = poly(0,'s');

xL7 = s*540e-9; xC7 = 1/s/5.5e-12; xC7A = 1/s/33e-12; xC7B = 1/s/33e-12;

Ri = 50; Ro = 50;

z1 = 1/(1/Ro+1/xC7B); z2 = xC7 + xL7; z3 = 1/(1/xC7A + 1/(z1+z2));

f = z3/(Ri+z3) * z1/(z1+z2);

xbasc(0); bode(syslin('c', f), 1e7, 9e9, .01);

Voila! A beautiful Bode plot. Even better if you do "set old_style on" first. With 50 ohm terminations, the resonant frequency is close to 100 MHz.

Reply to
Andrew Holme

Phase passes through 180 degrees around 125 MHz bode(syslin('c', f), 1.24e8, 1.26e8, .01);

Reply to
Andrew Holme

At the 94MHz or so frequency of interest, you convert the ends from parallel to series form.

33pF in parallel with 50R at 94 MHz transforms to 76pF in series with 30 ohsm.

Now your capacitance is 76 pF in series with 76 pF in series with 5p5. The

5p5 dominates.

Q at resonance is 1 / (2 Pi f C R ) = about 5. With such a low Q, the ends won't have that much effect on tuning. Especially if L7 is not adjustable, you would want a low Q or else component and construction variations would move your frequency around too much.

The end capacitors are there to set the Q and hence bandwidth and losses in the filter.

Roger Lascelles

Reply to
Roger Lascelles

Is there a formula for calculating the phase shift of the resonator circuit shown. That would be interesting to compare it with a computer calculated model.

Cheers, Kevin.

Reply to
Kevin Doyle

I just took the L7 C7 series resonant frequency to get in the ballpark. Using the transformed ends I could calculate a new resonant frequency, then recalculate the ends again etc.

Its quite common to do the transformation at one frequency then use the result over a narrow band of frequencies.

Easiest to just whack it into SPICE, 50 ohms source and load and look at the response.

The schematic looks as though non of the components is adjustable. In a commercial piece of equipment, you just might get away with selecting your components to give the pass frequency you want and always fitting the same brand and value parts onto the same PCB. Otherwise, you'd make L7 or C7 adjustable and tune it up.

Roger Lascelles

Reply to
Roger Lascelles

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