On Tue, 14 Jul 2009 08:01:08 -0700 (PDT), "Hamid V. Ansari"
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> wrote:
> >Dear friend,
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> >Regardly visit:
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formatting link
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> >I am a physicist having several innovations in physics (and also
> >mathematics).
> >The most important ones of them have been collected in the abovesite.
> >I've had much attempts for publishing some of them through physical
> >journals. If requested by email, you will find in your box some of the
> >viewpoints of the referees of some of these journals about some of
> >thes papers which show clearly that the framework of the papers is
> >scientific.
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> >Thanks for your attention
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> >Hamid V. Ansari
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> I have examined your treatment of the parallel plate capacitor and
> find your concepts to be quite na=EFve. =A0By introducing the capacitor a=
a pair of plates bearing +Q and -Q =A0you are repeating the same stupid
> approach taken by Panofsky and Phillips as they struggled to free
> themselves from the CGS charge-based triboelectric electrostatics at
> the time (1960 m/l) when SI was being introduced.
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> The plates are in fact merely electrodes allowing you to apply a
> potential difference (with a battery) in order to stress the
> dielectric, whether it is vacuum or plastic. The dielectric is the
> medium that stores the energy that is sucked out of the battery when
> you first connect it. Notice that in P&P's book there is nowhere
> mentioned the use of a battery in any instance.
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> The charge density S =A0is given by sigma =3D S =3D Veps/d =3D E*eps and =
this
charge density as a sheet exists all the way from plate A to plate B
> right through the dielectric, which at first is a vacuum.
> Disconnect the battery and connect and electroscope which will read
> voltage
> =A0 =A0 =A0 =A0 V =3D Sd/eps. =A0
> Now slide in a sheet of dielectric material k and the leaves will come
> together a bit. That's because of conservation of charge in this case
> that S remains the same. =A0Now we read the voltage
> =A0 =A0 =A0 =A0 V =3D Sd/eps*k
> V is reduced by the factor k because there are now k times as many
> polarizable charges, so less V is needed for the same S.
> Sears and Zemanski are all wet on this too, all this talk about the
> induced charges on the face of the dialectric. They have no idea how a
> capacitor works.
> When you disconnect the battery the voltage persists, because now the
> deflected charges are pushing back.
> John Polasek- Hide quoted text -
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In Paper 22 of this site I=92ve predicted that the magnetic levitation will fail if the experiment is performed in vacuum. Here I have no access to sufficient experimental facilities to test this prediction. Maybe you there can test this prediction like the same electronic engineer who could prove experimentally a prediction presented in Paper 6 and his report has been inserted in the paper.
Hamid V. Ansari