PUJT valley current?

A 2N6027, (running by itself, with 20mA Ig short circuit current available), pulls the cap down to about 0.56V.

The negative pulse at the Gate is only about 12uS wide.... roughly 3.2uS to discharge the cap, and then an 8.8uS recovery to the Off state.

______ ______9.44V | | | | | / | / \ / \/ __0.32V

I'm still running with the brute-force-and-ignorance zener diode scheme. A not-bad approximation for Iv (for the 2N6017) seems to be.

Guaranteed min Iv = 0.029*Ia + 0.041. All in mA.

Where Ia= Vg/Rg, over the range 1 mA to 50mA.

So an Iv of 0.4mA can be obtained with an Ia of 12.4mA.

Off the data sheet, the tempco of Iv looks to be about -1.4%/C, over the range 0 to 50C.

So an Ia of 1.5*12.4mA would be required for 50C operation.

--
Tony Williams.
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Tony Williams
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That formula works well! Continuing to permute the various feedback possibilities, this also works at "about" same frequency, 1KHz- the 10V zener only conducts on start-up: View in a fixed-width font such as Courier.

. .. . .. .. 18.8V .. | .. [45.7k] .. | .. 1n5240B 22n | .. +-----|OUT .. | \ | | .. | | | .. | | | .. +---[2.2k]-+-------+--[470]--G |A .. | | | _\|__ .. | | | \ /PUT .. | | | _\_/_ 2n6027 .. | | |+ |K .. --- [3.3k] === | .. - 20V | |10u | .. | | | | .. | | | | .. +----------+-------+-----------+--0v . .. . ..

Reply to
Fred Bloggs

ROTFLMAO!

...Jim Thompson

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|  James E.Thompson, P.E.                           |    mens     |
|  Analog Innovations, Inc.                         |     et      |
|  Analog/Mixed-Signal ASIC's and Discrete Systems  |    manus    |
|  Phoenix, Arizona            Voice:(480)460-2350  |             |
|  E-mail Address at Website     Fax:(480)460-2142  |  Brass Rat  |
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Reply to
Jim Thompson

In article , Fred Bloggs wrote:

Reply to
Tony Williams

Reposted below.

Reply to
Tony Williams

The trouble with supplying Ig(pk) from a capacitor is that Ig(avg), (0.3mA in the above circuit), has to be supplied by the 2.2k+3.3k resistive pot down.

I'm ok with the crude zener dropper atm. The frequency stability is not that important, and the 18.8V is not related to the 20V supply voltage.

For a PUT circuit where high Iv is req'd, and with better stability, perhaps the circuit below would be generally more useful.

--+-------+-------------------+Vs,20V | | | [R1] [R3] | |18k |1k | | | | | |/ [R4] V1+-----|npn |45.7k | |\e | | | +-----------+Vp | Vs+-----G |A | [R2] | _\|__ | |27k | \ /PUT | | | _\_/_ 2n6027 | | | |K ===C1 | [R5] | | 0.022uF | |100k | | --+-------+-------+-----------+--0v

Using a saturating emitter follower allows easy setting of the required maximum short circuit gate current, and has the benefit that the Vbe tends to cancel the offset voltage of the PUT, (Vp-Vs). So V1 is approximately equal to Vp.

Start the design by deciding on the Vp. Probably not greater than about 0.75xVs in order to avoid a dV/dT that is too slow at the trigger point. Then choose R4+C1 to get the required timing. Then make R3 to be less than R4/45 (for a 2N6027 running at up to 50C ambient temperature). Then calculate R1+R2 to get the required V1, but with the proviso that R1//R2 is less than 20x R3. Note that (if required) a frequency trimming pot can be placed at the junction of R1 and R2. Choose R5 for an emitter current of about 50-100uA at the lowest value of V1.

I think that squeezes the most out of a PUT... all we have to do now is to find somewhere to insert Jim T's mandatory flashing LED (probably best where the sun doesn't shine). :)

--
Tony Williams.
Reply to
Tony Williams

I read in sci.electronics.design that Tony Williams wrote (in ) about 'PUJT valley current?', on Thu, 24 Feb 2005:

Facing outwards, it could be the next fashion craze. May appear at the Oscar ceremony, even. (;-)

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Regards, John Woodgate, OOO - Own Opinions Only. 
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Reply to
John Woodgate

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