I have some problems about load line of this circuit...
Hints: Put in some perhaps arbitrary but possible numbers, like Vdd=3D
+5, Vss=3D-5, Rl =3D 1kohms. With the lower transistor shorted, the current in Rl is obviously 5mA. What happens as you vary Iq between, say, 0mA and 20mA? What can you tell me about Iq if both your equation and the equation in the picture are correct? Is the picture telling you that it is the only answer, or that it is a particular answer that may be interesting? You may also wish to consider the case where Vdd is not equal to -Vss, and how that changes the nice symmetrical picture.(Extra credit: what does that capacitance do to the load line in the case of sinusoidal excitation?)
Cheers, Tom
What you actually need is two load poly-lines. Cutoff in one part will actually occupy much but a minority of the active load line in the other part.
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