Oh! I didn't know such things existed. Hmm for ~$20 I could get a 100V supply. That might be fun... don't think of it as low current, it's a built in current limiter!
George H.
Oh! I didn't know such things existed. Hmm for ~$20 I could get a 100V supply. That might be fun... don't think of it as low current, it's a built in current limiter!
George H.
We'll never get along. Our definitions of "horrendous spikes" differ by 7 or 8 orders of magnitude.
What sets the frequency?
Depends on your definition of "quiet".
You "design" crap, I design elegance ;-) ...Jim Thompson
Those with half a brain ?>:-} ...Jim Thompson
Frequency is 1/2 the output slew rate divided by the total output voltage excursion. Output slew rate is just Vin/(Ri x Ci) of the integrator and output voltage excursion is your choice.
Makes no sense to me. Got a numerical example? Or Spice model?
Nice device. Could be used for driving isolated FET, with no need for auxiliary supply
Cheers
Klaus
The TLP3902 is a lot cheaper:
Cheers
Klaus
Yeah, that looks like the 'intended' application. I'll have to order a handful to play with.
George H.
I've done that; use my zero-standby-power opto-totem circuit, too.
That only makes 5 uA. Probably why it's cheaper... less silicon.
(There's also no stock in the US)
Hey, the TLP590B is a dip! I ordered 10 from mouser. I wonder what the noise is like on the output. With all the junctions in series I bet there's a bit of a temp coef. And then the shot noise will all add. (only in quadrature of course.)
George H.
I have none on-hand, but I wonder what you get if you take a 4N25, tie output device collector to emitter, call that cathode, and the base as anode... how much current do you get? ...Jim Thompson
I've got a tube of those... and the answer is,
I LED I sc (mA) (uA) ________________
10 47 20 96 30 143 40 188Hey if I un-short the collector and emitter I get a the same short circuit current out of one, but much less out of the other only 20uA for 10mA of LED current.
Care to guess, and then tell me why. If I hadn't done the measurement I would have guessed that I'd get less current out of each leg.
George H.
Not a lot. The efficiency is roughly CTR/beta.
Cheers
Phil Hobbs
I'm no expert in photo-induced currents in junctions, but my understanding is that most of it is in the base-emitter path.
(Perhaps because that junction is closest to the surface, but I'm just SWAG-ing :-)
Load it with Larkin's 60K and see what voltage you get. ...Jim Thompson
A few ma of supply rail spike with a few us risetime is quiet. A few amps in a few ns is noisy.
This is horrible, amps of shoot-through current with sub-ns rise:
You called 9 mA of slow spike "horrendous". Why?
I doubt that you could have designed any of my products. Well, maybe one of the trivial accessories.
There you go with the snot-nosed crap again. Why don't you grow up?
You expressly specified quiet, then posted a distinctly NOT-quiet schematic.
Could you design this...
Not a chance.
I'll be publishing the specifications, some 21 pages, once I cleanse it of any NDA issues.
I doubt you will be able to understand much more of it than the power supply consumption >:-} ...Jim Thompson
I tried a Cree T1-3/4 white LED and a Vishay VBPW34S photodiode. With
20 mA / 3 volts on the LED, carefully aligned, I get from the pd 0.52 volts open-circuit, 1.6 mA short-circuit current. That's a CTR of 8% and power transfer of, I'm guessing, around 1%.
If you use a longer wavelength LED, you should do better for power transfer, and maybe even CTR.
Cheers
Phil Hobbs
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