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You need current to drive a MOSFET - your driver must be able to source and sink enogh current needed to charge/discharge the Gate capacitance in the time you have available.
MOSFET switching time...
Jun 13, 2006
23 Replies
Thanks !
regards, vic
If you're using the 2N3904 to translate from the printer port's 3.5 V to your circuit's 10 v, you're using it as an inverter. This means that when the port pin is high the gate is low (off) and vice-versa. This also means you'll be fine without an extra resistor from gate to ground, the transistor gets to do that job. Just keep the pull-up (the one between collector and + 10 V) in a convenient range, somewhere between 4k7 and 22k, it's not very critical.
- YD.
Remove HAT if replying by mail.
Clifford Heath.
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