MOSFET problem

Apr 09, 2011 4 Replies

hi all



I wrote about FETs, and went ahead - with a BUZ100, seems better than BUZ72.



From my source,supplies with a LED for monitoring, and not pulse charing of a battery. It charges



But when I loose my power, the battery powers my LED on the other side of the FET.



Here it is: power in - to a LM555, output pin 3 directly to Gate and a resistor to ground. The power LED parralel with the LM555. Finally the FET between 0V and the battery connected to +V.



My problem is, that my BUZ100 is able to supply the other circuit when power is off, my LED is always on drainign the battery. I used the FET in order to avoid a diode and the loss involved.



What did I do wrong?



WBR Sonnich


It's hard to figure out what your circuit is, but you probably have leakage through the 555 too. There is a body diode with anode at the source and cathode at the drain which conducts reverse current through the FET without a gate volatge present. You need to do something like this:

view in a fixed-width font such as Courier.

. . . . . >----------------+------------------------------. . | | . | | . | | . | | . | ----- . | --- BATT . | | . .----------+ | . | | | . | | D| . | | G|- . POWER IN | ----- .----| . | | | PN3906 | |- . _ | | | S| . V ~~ | | PNP | | . - | 3-----+----E C-----+-[1K]-+ 2X BUZ100 . | | | | B | | . | | | | | | S| . [R] | | '-[1K]-+ | |- . | | | | '----| . | ---LM555 [5.6K] G|- . | | | D| . | | | | . >------+----------+---------------+--------------+ . | . | . --- . - . . .

Used a 555? Or did you use a 7555 or CMOS version? Please draw a circuit and post it, LTSpice is free, as is the ascii circuit software some here use (AAcircuit).

rcuit

Very useful information here. I was surprised that the 555 seems to cosume app 10ma, which for a solar project is a lot. I will try it with a 7555 ASAP to reduce power consuption. Thx

And for the programmes I have will check them out. Thx again. Schematic to come.

WBR Sonnich

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=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0-----

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 --- =A0BATT

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 D|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 G|-

=A0 =A0 =A0 .----|

=A0PN3906 =A0 =A0| =A0 =A0|-

=A0 =A0 =A0 =A0 =A0 =A0| =A0 =A0 S|

=A0 PNP =A0 =A0 =A0| =A0 =A0 =A0|

-----+-[1K]-+ =A02X BUZ100

=A0 =A0B =A0 =A0 =A0 | =A0 =A0 =A0|

=A0 =A0| =A0 =A0 =A0 | =A0 =A0 S|

=A0 =A0 =A0 | =A0 =A0|-

=A0 =A0| =A0 =A0 =A0 '----|

5.6K] =A0 =A0 =A0 =A0G|-

=A0 =A0 | =A0 =A0 =A0 =A0 =A0 =A0 D|

=A0 =A0 | =A0 =A0 =A0 =A0 =A0 =A0 =A0|

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 |

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 |

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0---

=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 -

I hope you're talking about lead acid batteries and not something else- last week it was a Sony Walkman. There are bunches of reference ciruits for PV charging of lead acid cells out there. If you visualize the body diode as in shunt with D-S terminals, then the back-to-back setup puts them in opposition, it is the only way to control bidirectional current flow with MOSFETs.

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