Electricity that doesn't require wires is called "lightning."
Trains that get their electricity from a third rail use the first two rails (which are connected together at various points) as part of the circuit. Electricians call this a "common" contact as opposed to the "hot" third rail.
Exactly what is it about the wiring of electric locomotives that frightens you?
A rotating Magnetic field will create a Current in a wire(I said a single long wire, not 2 pieces, no confusion here)
now, using this current in that single wire, how to make the bulb illuminates?
If I connect the one end of the wire to the '+' of the bulb and the '-' of the bulb to the earth.
By default, we are left with the other end of the wire as open.
There is Current in the wire by the effect of the rotating magnetic field, it would pass through the '+' of the bulb and there by to Tungsten(or whatever it is) and to '-' side of bulb there by to the earth.
then, why can't the Bulb illuminates? ==========
Procedure (2)
Instead of 1 single long wire, If I take 2 pieces of wires
One to the '+' of the bulb, other to the '-' of the bulb
at their both ends, if I joined them now the loop is closed.
If any rotating magnetic field produces the current in the wire the bulb will illuminates.
No the path isn't closed so no the bulb won't illuminate. You would also have to connect the copper electrode to earth as well.
It is possible to make an "apparently open" circuit work. For example some touch sensitive switches rely on capacative coupling of the human body to earth to close the circuit.
One of the more spectacular examples is with fluorescent tubes under pylons. Richard Box specialised in impressive dusk displays of this as artist in residence at Bristol University Physics dept.
No, the rotating magnetic field will create an electromotive force or potential (measured in volts) on the wire. The amount of current (measured in amps) that flows in the wire will be a function of the load placed from end-to-end on the wire (completing the circuit).
(remainder snipped due to invalid thought experiment assumption)
1) The coper electrode needs to recieve a supply of electrons or the chemical reaction in the battery stops.
2) The voltage across the bulb causes electrons to flow through it. If the right hand (+ve) side of the bulb was suddenly made open circuit, electrons flowing through the bulb would collect there (no place for them to go). This would reduce the voltage on that side of the bulb. Once the voltage across the bulb reaches zero no more electrons flow through the bulb.
Question - if you connect the copper electrode to earth, and the lamp to another earth 6 feet away, and the battery is 3VDC, would the lamp still light?
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