But if the spheres are orbiting each other (and tidally locked), where's the relative velocity? I don't see it.
There's G in the formula. Where's anti-G? Centri-fug/pet-al force?
But if the spheres are orbiting each other (and tidally locked), where's the relative velocity? I don't see it.
There's G in the formula. Where's anti-G? Centri-fug/pet-al force?
Tangential or angular, however you might think of it.
Linear (translational, unaccelerated) motion cancels out in relativity, but not rotational (angular, accelerated).
Huh?
Tim
-- Seven Transistor Labs Electrical Engineering Consultation Website: http://seventransistorlabs.com
Still not seeing it. We're talking about the velocity of either one as witnessed by the other, right? There isn't any. The universe is revolving around them.
It has to. Look at the rider on the other side of the merry-go-round.
(2 * pi * sqrt((1 (m^3)) / (G * 1 kg))) / 4 =
2.22545204 days
Rotational motion can be detected, even if it is with a constant angular velocity. For example you will get Coriolis forces.
Contrary to that a common constant linear motion cannot be detected. All inertial frames are equivalent.
-- Reinhardt
On Friday, December 26, 2014 9:35:39 AM UTC-6, snipped-for-privacy@gmail.com wrote:
5.5 nanosecondsw primitive coefficient : G(N)/G(D)
nservation of continuum rules the force of interplanetary gravity.
1/(300000000/(1/(5.5 x 10^-9))) = 0.606060606061/(0.6) = 5/3 = 1.6666666667
1/ 0.006 = 166.6666666671/.00006 = 16666.6666667
etc ....
10 squared ) squared )squared )squared ) "Fractal"Proton-to-electron mass ratio as the curvature of the universe ? = mp/me = 1836.15267245 = 0.0054461702177830795335942599711
461 1 + 0.0054461702177830795335942599711461 1.0054461702177830795335942599711461 180 degrees = 0.3120394829027676 degrees = 180.3120394829027676 180 / 180.3120394829027676 = 0.99826944732 = 1 / 1.0017335 1.0017335526842436390232846979164 - 1 = 0.0017335526842436390232846979 164 0.0017335526842436390232846979164^10 = 2.409063 x 10^-2810^-14
7 = 1/1445.482D
Difference = 300000000 x 0.99930819635258 = 299792459
1 / 0.99930819635258 = 1.0006922825710276822457954300555 - 1 =0.0006922825710276822457954300555
Curvature of Truncated Octahedral Lattice = 1 / 1444.4968598
= 5.5 nanoseconds
new primitive coefficient : G(N)/G(D)
conservation of continuum rules the force of interplanetary gravity.
vEvKQJ
11461 79164_angle
7le
9Sqrt ( 10Sqrt ( 2) = Sqrt ( 1.0006771306930663566781727848746^2) = 2
he spatial geometry is spherical, i.e. possess positive curvature, the topo logy is compact. For a flat (zero curvature) or a hyperbolic (negative curv ature) spatial geometry, the topology can be either compact or infinite.[9] Many textbooks erroneously state that a flat universe implies an infinite universe; however, the correct statement is that a flat universe that is al so simply connected implies an infinite universe.[9] For example, Euclidean space is flat, simply connected and infinite, but the torus is flat, multi ply connected, finite and compact.
local geometry to the global geometry. If the local geometry has constant curvature, the global geometry is very constrained, as described in Thursto n geometries.
ts (like SKA, Planck..) will not be able to distinguish between flat, open and closed universe if the true value of cosmological curvature parameter i s smaller than 10^?4. If the true value of the cosmological curvatu re parameter is larger than 10^?3 we will be able to distinguish be tween these three models even now.[10]
png Bohr's formula gives the right Hydrogen energy spectrum.
11x 10^-14
157 = 1/1445.48Electron frequency = 1.2356 x 10^20
Gravity = Electron frequency^2 / 10D space
1.5267074e+39
= 5.5 nanoseconds
new primitive coefficient : G(N)/G(D)
conservation of continuum rules the force of interplanetary gravity.
vEvKQJ
11461 79164
_angle
7le
9Sqrt ( 10Sqrt ( 2) = Sqrt ( 1.0006771306930663566781727848746^2) = 2
he spatial geometry is spherical, i.e. possess positive curvature, the topo logy is compact. For a flat (zero curvature) or a hyperbolic (negative curv ature) spatial geometry, the topology can be either compact or infinite.[9] Many textbooks erroneously state that a flat universe implies an infinite universe; however, the correct statement is that a flat universe that is al so simply connected implies an infinite universe.[9] For example, Euclidean space is flat, simply connected and infinite, but the torus is flat, multi ply connected, finite and compact.
local geometry to the global geometry. If the local geometry has constant curvature, the global geometry is very constrained, as described in Thursto n geometries.
ts (like SKA, Planck..) will not be able to distinguish between flat, open and closed universe if the true value of cosmological curvature parameter i s smaller than 10^?4. If the true value of the cosmological curvatu re parameter is larger than 10^?3 we will be able to distinguish be tween these three models even now.[10]
png Bohr's formula gives the right Hydrogen energy spectrum.
11x 10^-14
157 = 1/1445.48On Monday, December 29, 2014 10:08:11 AM UTC-6, snipped-for-privacy@hotmail.com wrote :
te:
= 5.5 nanoseconds
e new primitive coefficient : G(N)/G(D)
a conservation of continuum rules the force of interplanetary gravity.
SivEvKQJ
97114616979164
he_angle
^-7
ngle
( 9Sqrt ( 10Sqrt ( 2) = Sqrt ( 1.0006771306930663566781727848746
2)^2) = 2the spatial geometry is spherical, i.e. possess positive curvature, the to pology is compact. For a flat (zero curvature) or a hyperbolic (negative cu rvature) spatial geometry, the topology can be either compact or infinite.[
9] Many textbooks erroneously state that a flat universe implies an infinit e universe; however, the correct statement is that a flat universe that is also simply connected implies an infinite universe.[9] For example, Euclide an space is flat, simply connected and infinite, but the torus is flat, mul tiply connected, finite and compact.he local geometry to the global geometry. If the local geometry has constan t curvature, the global geometry is very constrained, as described in Thurs ton geometries.
ents (like SKA, Planck..) will not be able to distinguish between flat, ope n and closed universe if the true value of cosmological curvature parameter is smaller than 10^?4. If the true value of the cosmological curva ture parameter is larger than 10^?3 we will be able to distinguish between these three models even now.[10]
1.png Bohr's formula gives the right Hydrogen energy spectrum.^-11
2 x 10^-14 81157 = 1/1445.48Gravity .... Entropic
Interesting example!
Yes, a bullet, or a beam of light, fired from one to the other will miss its target.
Will gravity miss?
No, but according to general relativity you will see the Lense-Thirring-Effect. It has been measured with the Gravity-Probe-B Satellite
-- Reinhardt
Oh, okay. Well then, in that case, never mind.
I didn't pick up anything about the orbiters closing in and making contact.
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