Current sense transormer to detect current surge in DC link?

Jan 21, 2008 4 Replies

I know current sense transformers are use for measuring AC currents. I'd like to use one to the measure a DC link at 1A that could have a rapid surge to 10A (like in 1uS).



I only want to detect the surge and not read the SC level. I'd also like for it to be small since I'm only interedted in the surge. It doesn't even have to be accurate as I only need to detect the presence of the surge.



Would a small cored ferrite transformer something like 0.700"OD or smaller saturate from the DC current and not detect the high frequency surge?


I might get this wrong but here goes...

Ferrite toroids: ~5000 gauss sat level

Field intensity H = (0.4*pi*NI)/l amps,turns,cm

Perm. ui = B/H gauss,oersteds

Ferrite perm ur: Ugh! There's all different types!

Oh..I'll just make one up :P

Let's say ur = 3000

Free space perm u = 1.257 x 10E-6 Henrys/m

Since ur = ui/uo

ui = uo*ur

Hsat = Bsat/ui

Then solve for N (turns) using 1A and the magnetic pathlength for a

0.7 OD toroid, you should be able to solve for the limit for turns to avoid saturation.

There's also a crapload of technical detail that can mess up the math. So even if I got it right, it's probably still wrong. :P

OR.. You can skip all that math and just look at a bunch of datasheets. The inductance and current are often spec'd.

D from BC British Columbia Canada.

The "surge" as you call it is an AC signal. THe current transformer core must not saturate in the presence of the DC current; so a dinky ferrite transformer will not do. Ferrites are generally for high frequency - say from 10KC to 100MC, where laminated iron cores aer gneerally for low frequencies - say from

10Hz to 10Kc.

From what you've described, it sounds like you should consider air cored. Depending on your accuracy requirement, there might still be some design involved, but you don't need to worry about magnetic material behaviour, meaning that you can ignore saturation caused by the DC.

Well, I'd say this all depends on Mook's meaning of "small", and your meaning of "dinky". A single turn carry 1A would not saturate most small cores I'm thinking of, but then, what does "small" mean to me? Anyway, one turn through the middle of a "small" toroid core, 100 turns wrapped around it, and a 27-ohm load resistor, will give a 2.7-volt output pulse when Mook's 10A current spike arrives.

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