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BestPair II Voltage Divider Resistor Pair Picker Software

Hi, There are 480,000 different combinations of standard 1% resistor values. If you need 2.75 volts from a 5.00 volt reference, which of those 480,000 pairs will give you the closest result?

For this example there are 9 resistor pairs that will get you to within

0.5%, but one resistor pair will get you within 0.15%. Only 1 out of 480,000 combinations is the best pair!!

BestPair has been upgraded to Best Pair II. If you are interested you can get it with instant download delivery here -->

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Thanks for looking.

Cheers, Tim

Reply to
Tim
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Thanks for having a look at my app doing the same for free :

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Rene

--
Ing.Buero R.Tschaggelar - http://www.ibrtses.com
& commercial newsgroups - http://www.talkto.net
Reply to
Rene Tschaggelar

If

pairs

480,000

There are several problems with this.

  1. YOu can not be sure of getting .5 % or less error if you have 2 of the 1 % resistors to start with.
  2. You did not list the resistance of the source and load. If the source will not supply the needed current for low values, they are out. If you have a low resistance load , the resistors will have to be on the low end of the standard values.
Reply to
Ralph Mowery

How about my silly javascript version:

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No download required at all...

--
Regards,
  Bob Monsen

"I cannot persuade myself that a beneficent and omnipotent God would
have designedly created parasitic wasps with the express intention of
their feeding within the living bodies of Caterpillars"
 -- Charles Darwin
Reply to
Bob Monsen

Laydeeze and Gennelmun, I believe we have us a weiner! ;-D

Cheers! Rich

Reply to
Rich Grise, but drunk

Cool, but I often find I havnt got a full set of resistors and so if I want to make a divider thats more exact than i can make with any 2 of the ones I have I have to fiddle about trying to work out what set of 3 resistors that I do have in series/parallel whatever combination will give the best result.

(I realy must get some 9k resistors, I so often want to make a 10x non inverting op amp gain stage)

Colin =^.^=

Reply to
colin

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