74act high output curve (voltage vs current)

I would expect it to look pretty much resistive, until you start to run out of IDSS.

...Jim Thompson

--
|  James E.Thompson, P.E.                           |    mens     |
|  Analog Innovations, Inc.                         |     et      |
|  Analog/Mixed-Signal ASIC\'s and Discrete Systems  |    manus    |
|  Phoenix, Arizona            Voice:(480)460-2350  |             |
|  E-mail Address at Website     Fax:(480)460-2142  |  Brass Rat  |
|       http://www.analog-innovations.com           |    1962     |
             
I love to cook with wine.      Sometimes I even put it in the food.
Reply to
Jim Thompson
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I'm looking to power an array of 32 small 5V 4 - 6mA devices with the outputs of a 74 ACT bus driver or similar. I'm doing ths because I only power one device at a time and only for a short period of time (say 200mS then off for 1 second).

I know the 74AC(T) line is rated for 24mA output current but I would like to know the output voltage drop as the current increases from 0 through 24mA (a curve). Or more specifically what the voltage is at 5mA draw. I need the voltage to be fairly stiff as the output of these devices are ratiometric with the supply voltage.

The datasheets only specify Voh at a few uA and at 24mA output. I don't think voltage drop would be linear (might be).

I know the proper way is to use a bank of low RDS p-mos but I'm trying to reduce parts count.

Reply to
Mook Johnson

Even if there was an IV curve it would just be "typical." From the data sheet of the TI 74AC244 you can infer that RDS,ON of the pull-up PMOS is no more than 27 ohms from the minimum Voh specifications, and this seems to be the limit in the Vcc=4.5 to 5.5 volt range. At your 6mA load, this makes for a 0.006 x 27=0.16V drop which amounts to 0.16/5= -3.2% just due to the driver. The typical might only be -2.5%, which may or not be considered "stiff" depending on the load tolerance.

Reply to
Fred Bloggs

Hello Mook,

It'll be different from device to device as Fred had hinted. So if you have 32 loads driven by four chips and one of the chips happens to orginate from a different batch or date code you may have a discrepancy in RDSon and thus voltage.

Why not replace them with some stiff ULN driver? These come in SO packages. or do you need the speed?

Regards, Joerg

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Reply to
Joerg

Looks interesting but the forward drop looks like its 0.6V even at low currents.

Reply to
mook Johnson

[snip]

WRONG current direction, you're measuring the ESD diode.

Put a 74ACT... into an output high state, load output with a resistor to ground (various values), THEN you will know how much load it can support.

...Jim Thompson

-- | James E.Thompson, P.E. | mens | | Analog Innovations, Inc. | et | | Analog/Mixed-Signal ASIC's and Discrete Systems | manus | | Phoenix, Arizona Voice:(480)460-2350 | | | E-mail Address at Website Fax:(480)460-2142 | Brass Rat | |

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| 1962 | I love to cook with wine. Sometimes I even put it in the food.

Reply to
Jim Thompson

You can find IBIS models for various parts here

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The models are not that easy to read but do effectively contain plots of pin current against pin voltage.

I get confused about which way round the pullup and pulldown plots are used and what the reference for the voltage is but it looks to me like an ACT244 would typically be dropping about 70mV at 5mA either way.

Reply to
nospam

Hello Mook,

Shouldn't be 0.6V even with bipolar outputs but you'd have to find one with FETs. If the load absolutely has to be grounded look for 'high side drivers', else for 'low side' (easier). Some of them can sink an incredible amount of current and thus offer a very low RDSon.

Regards, Joerg

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Reply to
Joerg

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