I ordered the headphone amp from Oatley Electronics and it arrived yesterday. Reading the instructions and the explanation of how it works has me a little confused. Refer to this link:
- posted
8 years ago
I ordered the headphone amp from Oatley Electronics and it arrived yesterday. Reading the instructions and the explanation of how it works has me a little confused. Refer to this link:
My guess is that it's a case of matching impedance. Headphones are, effectively, a resistor (600 ohms or less). Hooking that resistor to the anode of the tube (even through a capacitor) might cause the tube stage to malfunction, whereas the op-amp is designed to handle that load.
So it's basically converting a 600 ohm load into a 1 Mohm load.
To clarify, it has a _power_ gain significantly more than one, but a _voltage_ gain of 1.
(Driving low-impedance things from a gain-of-one amp that's driven by a high-impedance thing is fairly common, BTW)
-- www.wescottdesign.com
The VOLTAGE gain is 1, the current gain is not. There is therefore a power gain.
The outputs in almost any normally designed stereo are simply current gain. The voltage gain is ahead of that. Ir you took off your speaker outputs at the voltage stage you might blow it, and it CERTAINLY will not work proper ly because it cannot supply the current for a low impedance load.
You would have to have a bunch of tubes in parallel to supply even the meag er current for dynamic headphones. An IC inherently has better quality than a transformer, unless you are looking for non linearity in power bandwidth or the voltage itself.. Old tube guitar amps do this and even react with t he speaker impedance to give a certain sound which is actually sought after . Also, certain hifi tube amps have interactions that make the more suitabl e for certain speakers. Solid state is a different story, and that is why s ome people like tube amps.
There are tube driven solid state amps, solid state driven tube amps, they all have their own characteristics. Your headphone amp is tube driven solid state. I am not exactly sure what is the allure. Depletion mode FETs shoul d act almost exactly like triodes but apparently do not. That is why people buy tube amps.
** See the 180kohm resistors in the anode circuit of each valve? That is their best operating impedance, your headphones may well be 32 ohms so there is one hell of a mismatch. The amplifier IC is designed to drive 32ohm loads and deliver enough power to go quite loud - which the tubes alone could never do.
.... Phil
Thanks Tim, that makes sense. Does increasing the gain of the IC amp raise just the available current or does the voltage also increase with the current? Eric
Thanks for the reply Jurb. So is part of the reason the xmfrs for tube amps are so expensive because they need to be wound a certain way to get good sound? Or is it all mostly hype? I have heard tube amps that sound very good to my ears but all my amps but the one I just built are all solid state and they sound very good too. Eric
Amps are typically voltage controlling devices. A certain gain means that Vout/Vin = gain. An amp will also have a maximum current. So as you change the load on the amp you will see the voltage remain (approximately) constant, and the current change to meet whatever the load is. Until you reach the maximum current at which point the amp will typically output a reduced voltage... V = I_max*R_load.
George H.
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