Hello,
I know little about electrical issues, so I am looking for some help answering two questions:
- I have a cordless drill with an 18V nicad pack. At some point, the charger failed (no voltage measured off the leads). I took the charger transformer apart, found a tripped thermal fuse (only because it was outside the coils) and replaced it. The charger worked again. I started to charge the battery pack, but found that the tranformer was getting very hot again. I measured the voltage in the battery pack after 10 minutes of charging (the transformer was very hot by then) and it was 12V. So I took apart the battery pack. Inside were 15 4/5 Sub C nicad cells. 9 of the cells measured 1.2-1.3 volts on the voltmeter. 6 of the cells measured 0 volts. Hence the ~12V I guess.
So here's the question: what about this battery pack makes the transformer heat up to the point it burns out? There doesn't seem to be a short in the battery pack, just a few bad cells. . .I don't understand why this gives the transformer such grief.
- While I was messing with this issue, I needed a drill. I went to Freight Harbour and bought a very cheap () 18V cordless drill to tide me over. The battery pack that comes with it is rated at ~19V. I tested the output from the pack and it was 19.2V. However, the charger that comes with it is rated at 24V (or it says so on the wall plug). So I figured they buried a resistor in there somewhere. However, I tested the output from the charger -- 24.1V. So here's the question:
Will using this 24V charger on the 19.2V pack damage the charger or the battery pack? I understand that this is a really cheap drill, but how can they in good conscience provide a mismatched charger/pack? Is it because 24V transformers are so cheap?
Thanks for those who bother to read all of this.
Ed.