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A solution not to do dependency check?
- 10-16-2008
October 16, 2008, 12:48 am

In my Makefile, there is the following target such as "config".
...
config:
@make -C ./config || exit $?
...
but, there is a directory the same as "config" for name.
So, if I try to make as "make config", the following message is printed.
"make: `config' is up to date."
I guess the make checks date of "config" directory and decided that make is
not needed.
In this case,
I want to make absolutely without dependency check.
Is there a good solution?
[root@test] ls
config Makefile
[root@test] make config
make: `config' is up to date.
[root@test]
...
config:
@make -C ./config || exit $?
...
but, there is a directory the same as "config" for name.
So, if I try to make as "make config", the following message is printed.
"make: `config' is up to date."
I guess the make checks date of "config" directory and decided that make is
not needed.
In this case,
I want to make absolutely without dependency check.
Is there a good solution?
[root@test] ls
config Makefile
[root@test] make config
make: `config' is up to date.
[root@test]
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