Pulsing LEDs to achieve maximum output?

Ok,

I've read some discussion here about pulsing LEDs to achieve higher output without burning the stupid things out. (Instead of CW).

I'm just working on a circuit for general purpose low voltage illumination, but want to achieve maximum output.

I suppose a pulse of 100Hz would be decent? This would allow more voltage to be applied to the LED without overheating it.

So I was thinking of using a 555timer triggering a transistor (of what type?) handling approx 25 LEDs (no specific data on the LED yet, I haven't gotten that far ie: current, voltage, etc..., I'm researching that now).

I have a basic schematic that shows a 555 triggering such a circuit, just what transistor should work for me if I want to lets say switch a 6VDC/1A load?

Any info would be great, thanks!

BTW: I believe it was "Watson" that was telling us about his white LEDs that weren't lasting very long, well, I've been seeing a lot more white LED applications such as crossing lights, while the duty cycle is quite low, I suppose they expect these crossing lights (you know the picture of the person walking!) to last quite a while.

From what I understand, the Osram LEDs are of excellent quality, and priced a wee bit higher than the rest as well.

--
Myron Samila
Toronto, ON Canada
Samila Racing
http://204.101.251.229/myronx19
Reply to
Myron Samila
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without burning

illumination, but want to

to be applied

type?) handling

ie: current,

what transistor

that weren't

applications such as

these crossing

while.

priced a wee bit

Read the last thread and you will see that pulsing leds REDUCES the output compared to that obtained by the same average current at dc.

Reply to
R.Lewis

I guess the theory is you could supply more V at the junction, letting it cool in the off period, and get higher output, but you're also switching it on and off (quite possibly reducing output than if CW)

The idea is to get the LEDs to last long, ideally, my simple illumination project would consist of nothing more than a simple bank of LEDs, and a voltage regulator! (skipping any of the pulsing)

--
Myron Samila
Toronto, ON Canada
Samila Racing
http://204.101.251.229/myronx19
Reply to
Myron Samila

Why not use a few more LEDs then run at a lower setting.

More light less loss!!

Regards, Gordon.

output

voltage

far

just

LEDs

expect

output

cool in the off

(quite possibly

project would

regulator! (skipping

Reply to
Gordon Youd

cool in the off

(quite possibly

The problem is the eye sees the average brightness. Put simply if you double the power into the LED but for only half the time you get no change. (Even that assumes that the LED power efficiency is constant for all power inputs.)

This trick does work under certain conditions but typically the frequency and mark space ratio has to be low enough for the flashing to be seen. For example 0.25 second ON, 2 seconds OFF.

project would

regulator!

Actually you need a current regulator not a voltage regulator but that's being picky.

Colin

Reply to
CWatters

Hi Colin,

Curious, lets say I have 10 LEDs that draw 20mA each, so 200mA total at lets say the breakover voltage is 2.0V, wouldn't a 7802 (if they even have regulators that small, 7805 common enough) be able to regulate it?

With the "7802" regulator, you'd be able to handle 50 LEDs (1A) I suppose, if my calculations are correct.

I just don't want to burn out a ton of LEDs cuz I could have done something different, research first, then try it ;). Carpenters measure twice, cut once.

--
Myron Samila
Toronto, ON Canada
Samila Racing
http://204.101.251.229/myronx19
Reply to
Myron Samila

lets say the

that small, 7805

I did say I was being picky....

LED's act like a "constant voltage sink" so if you want to connect them to a voltage source you need to put something in series to limit/regulate the current. You can use a resistor in series to limit the current.

Using your examples...

R = (Vs-Vled)/I R = (5-2)/0.02 = 150 R.

and the power dissipated in the resistor is

P = 3 * 0.02 = 60mW

so 1/8th W resistors are OK.

You could try putting two LED in series with each resistor and recalculate the value needed as...

R = (5-4)/0.02 = 50 R

and then

P = 20mW

Basic maths says that if you want an accurate answer to an equation (eg accurate control of the current) you should avoid subtracting one number from another similar one (eg avoid Vs-Vled approaching 0!).

On the other hand the larger the voltage drop across the resistor the less sensitive the curcuit is to resistor and LED tollerance - so you may not need a voltage regulator at all (but watch the power dissipation in the resistor if it's very large).

Overall you need to balance these issues.

What is the source voltage? (eg input to the regulator).

Colin

Reply to
CWatters

Essentially, Vs can be just about anything at this point, I will design around the load requirements. It will be stepped down from AC, rectified and filtered.

Thanks for the info, I'm trying to source out a local supplier for some white LEDs of good quality and of the output I require (the more mcd the better).

--
Myron Samila
Toronto, ON Canada
Samila Racing
http://204.101.251.229/myronx19
Reply to
Myron Samila

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